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23 Sep 2021, 02:30
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B
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Difficulty:
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61% (02:44) correct
39%
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wrong
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The integers 1 through 5 are written on each of five cards. The cards are shuffled and one card is drawn at random. That card is then replaced, the cards are shuffled again and another card is drawn at random. This procedure is repeated one more time (for a total of three times). What is the probability that the sum of the numbers on the three cards drawn was between 13 and 15, inclusive?
A. 1/25
B. 2/25
C. 3/25
D. 4/25
E. 1/5
A. 1/25
B. 2/25
C. 3/25
D. 4/25
E. 1/5
23 Sep 2021, 04:12
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total no of outcomes = 25
favourable outcomes = 4 i.e (5,5,5 / 5,5,4 / 5,4,4 / 5,5,3)
IMO ans D
favourable outcomes = 4 i.e (5,5,5 / 5,5,4 / 5,4,4 / 5,5,3)
IMO ans D
RanonBanerjee
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25 Sep 2021, 00:26
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Ans: 2/25 (B).
Total number of outcomes: 5^3=125
13 if outcomes are (5,4,4 and 5,5,3) which can be arranged 6 ways (544, 454, 445 & 553, 355,535) respectively.
14 if outcomes are 554 with 3 arrangements (554,545,455)
15 only if we have 555. I.e, only 1 arrangement is possible.
Probability= (6+3+1)/125 =10/125= 2/25
Posted from my mobile device
Total number of outcomes: 5^3=125
13 if outcomes are (5,4,4 and 5,5,3) which can be arranged 6 ways (544, 454, 445 & 553, 355,535) respectively.
14 if outcomes are 554 with 3 arrangements (554,545,455)
15 only if we have 555. I.e, only 1 arrangement is possible.
Probability= (6+3+1)/125 =10/125= 2/25
Posted from my mobile device
