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Updated on: 29 Mar 2022, 08:48
Originally posted by Rohansaini1997 on 29 Mar 2022, 08:45.
Last edited by Bunuel on 29 Mar 2022, 08:48, edited 1 time in total.
Last edited by Bunuel on 29 Mar 2022, 08:48, edited 1 time in total.
Renamed the topic and edited the question.
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Difficulty:
35%
(medium)
Question Stats:
79% (02:37) correct
21%
(02:42)
wrong
based on 223
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Daniel drove a 880-mile distance in two days. In the first day, he drove a certain part of it and his car consumed 20 gallons of fuel. In the second day, he drove the remaining distance and his car consumed again 20 gallons of fuel. If the mileage (miles traveled per gallon) of his car in the second day was 20% greater than the mileage of his car in the first day, what was the mileage of Daniel’s car in the first day?
A. 35
B. 30
C. 25
D. 20
E. 15
Sol- Total Distance=880 miles
Total Fuel Consumed= 20+20= 40 gallons
Mileage for 2 days= 880/40= 22 miles/gallon
first and second day's mileage equals 22.
if we take the mileage of first day as x, then second day's mileage would be-
22-x= x+0.2x
22-x=1.2x
22=2.2x
10=x (first day's mileage)
A. 35
B. 30
C. 25
D. 20
E. 15
Show SpoilerCan anyone advise what is wrong in my solution below?
Sol- Total Distance=880 miles
Total Fuel Consumed= 20+20= 40 gallons
Mileage for 2 days= 880/40= 22 miles/gallon
first and second day's mileage equals 22.
if we take the mileage of first day as x, then second day's mileage would be-
22-x= x+0.2x
22-x=1.2x
22=2.2x
10=x (first day's mileage)
29 Mar 2022, 09:16
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Rohansaini1997
Hello, Rohansaini1997. To address your query, the first half of your solution is fine. All you need to do is keep your eye on the average. If the mileage of the first day is x, then the mileage of the second day is 1.2x. Then, you just have to set up an equation based on the information you have worked out:
\(\frac{x + 1.2x}{2}=22\)
\(x + 1.2x = 44\)
\(2.2x = 44\)
Here, I multiplied through by 10, since I find working with whole numbers much less likely to lead to errors.
\(x = 20\)
Perhaps the question makes more sense now. Good luck with your studies.
- Andrew
29 Mar 2022, 09:49
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Given: Daniel drove a 880-mile distance in two days. In the first day, he drove a certain part of it and his car consumed 20 gallons of fuel. In the second day, he drove the remaining distance and his car consumed again 20 gallons of fuel.
Asked: If the mileage (miles traveled per gallon) of his car in the second day was 20% greater than the mileage of his car in the first day, what was the mileage of Daniel’s car in the first day?
Let the distance travelled on the first day be x miles
Distance travelled on second day = 880 - x miles
Mileage for first day = x/20 miles/gallons
Mileage for second day = (880-x)/20 miles/gallons
The mileage (miles traveled per gallon) of his car in the second day was 20% greater than the mileage of his car in the first day
1.2x/20 = (880-x)/20
1.2x = 880-x
2.2x = 880
x = 400 miles
Mileage on first day = 400/20 = 20 miles/gallons
IMO D
Asked: If the mileage (miles traveled per gallon) of his car in the second day was 20% greater than the mileage of his car in the first day, what was the mileage of Daniel’s car in the first day?
Let the distance travelled on the first day be x miles
Distance travelled on second day = 880 - x miles
Mileage for first day = x/20 miles/gallons
Mileage for second day = (880-x)/20 miles/gallons
The mileage (miles traveled per gallon) of his car in the second day was 20% greater than the mileage of his car in the first day
1.2x/20 = (880-x)/20
1.2x = 880-x
2.2x = 880
x = 400 miles
Mileage on first day = 400/20 = 20 miles/gallons
IMO D
