Rohansaini1997
Daniel drove a 880-mile distance in two days. In the first day, he drove a certain part of it and his car consumed 20 gallons of fuel. In the second day, he drove the remaining distance and his car consumed again 20 gallons of fuel. If the mileage (miles traveled per gallon) of his car in the second day was 20% greater than the mileage of his car in the first day, what was the mileage of Daniel’s car in the first day?
A. 35
B. 30
C. 25
D. 20
E. 15
Hello,
Rohansaini1997. To address your query, the first half of your solution is fine. All you need to do is keep your eye on the average. If the mileage of the first day is
x, then the mileage of the second day is 1.2
x. Then, you just have to set up an equation based on the information you have worked out:
\(\frac{x + 1.2x}{2}=22\)
\(x + 1.2x = 44\)
\(2.2x = 44\)
Here, I multiplied through by 10, since I find working with whole numbers much less likely to lead to errors.
\(x = 20\)
Perhaps the question makes more sense now. Good luck with your studies.
- Andrew