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08 May 2022, 02:42
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
87% (02:19) correct
13%
(02:57)
wrong
based on 263
sessions
History
Date
Time
Result
Not Attempted Yet
Four employees, Mark, Ellen, Dennis, and Jane, were given a certain amount of money to spend on lunch. Mark spent $3 less than 1/3 of the total amount; Ellen spent $2 more than 1/4 of the total amount; Dennis spent 1/4 of the total amount; and Jane spent $7. If all of the money, and no additional amount, was spent, what was the total amount given to the four employees?
A. $32
B. $36
C. $42
D. $45
E. $48
Source: Skills Insight
A. $32
B. $36
C. $42
D. $45
E. $48
Source: Skills Insight
24 Jun 2022, 23:05
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Bunuel
Look at the answer choices. We (almost certainly) need something that results in an integer when we take 1/3 and also results in an integer when we take 1/4. A, C, and D are all out. Let's try B.
$36 total.
Mark spent $3 less than $12, so Mark spent $9.
Ellen spent $2 more than $9, so Ellen spent $11.
Dennis spent $9.
Jane spent $7.
Does 9+11+9+7=36? Yep.
Answer choice B.
General Discussion
08 May 2022, 15:24
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Suppose total amount given to spend was P.
Mark spent (P/3)-3.
Ellen Spent (P/4)+2
Dennis Spent P/4
Jane spent 7$
so, according to question, (P/3)-3 + (P/4)+2 +(P/4) +7 = P
Solving this, P= 36$. OB.
Mark spent (P/3)-3.
Ellen Spent (P/4)+2
Dennis Spent P/4
Jane spent 7$
so, according to question, (P/3)-3 + (P/4)+2 +(P/4) +7 = P
Solving this, P= 36$. OB.
