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Step 1: Divide available weight by the ratio part
Find how many "multiplier units" each nutrient allows:
Nitrogen (N): 18/5 = 3.6
Phosphorus (P): 14/4 = 3.5 (Lowest -> Limiting Factor)
Potassium (K): 20/1 = 20

Step 2: Multiply the lowest multiplier by the sum of the ratio
The sum of the ratio parts is 5 + 4 + 1 = 10
Max Fertilizer = 3.5 * 10 = 35 Kg

Correct Answer: B
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5:4:1=10x (10kgs will have 5kg of N, 4Kg of Phos. and 1Kg of Potassium)
This way 30 kgs is directly possible ; we are left with 3 kgs of N and 2 Kgs Phos. and ample of Potassium) 5/10=1/2kg of N is needed in 1Kg of mixture so it can go up to 36kgs, but 4/10=0.4 in every 1kg mixture and 0.4*5=2 (12+2=14 kgs available in total) making the answer 30+5 kgs
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