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Aabhash777
On Sunday, Ron begins to drive due north from point T at a constant rate of x miles per hour. Two hours after Ron started, Sam begins to drive due south from point T at a constant rate of y miles per hour. If y>4x, for how many hours Ron would have driven when Sam had covered thrice as much distance as Ron?

A. x/(x - 2y)
B. 2y/(x - 3y)
C. 2y/(y - 3x)
D. 2x/(x + 4y)
E. 2x/(y - 3x)

Ron travels for x mph for 2 hrs. Say x = 1 so he travels 2 miles in 2 hrs.
Sam begins and say drives for an hour. Ron covers 3 hrs in this time and Sam should cover three times that i.e. 9 miles in 1 hr. So y = 9 mph (y > 4x so this constraint is satisfied).
Ron has driven for 3 hrs at this time.

Put x = 1 and y = 9 in the options. Only option (C) gives 3 hrs. (Options A and B are negative and D and E are less than 1)

Answer (C)
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Aabhash777
On Sunday, Ron begins to drive due north from point T at a constant rate of x miles per hour. Two hours after Ron started, Sam begins to drive due south from point T at a constant rate of y miles per hour. If y>4x, for how many hours Ron would have driven when Sam had covered thrice as much distance as Ron?

A. x/(x - 2y)
B. 2y/(x - 3y)
C. 2y/(y - 3x)
D. 2x/(x + 4y)
E. 2x/(y - 3x)

I worked this way.

Lets y drove t hours.
so, ty= 3(2x+tx)
ty-3tx=6x
t(y-3x)=6x
t=6x/(y-3x)

so ron drove 6x/(y-3x)+2 hours
which gives 2y/(y-3x)
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