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03 Oct 2022, 02:11
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
57% (01:53) correct
43%
(02:26)
wrong
based on 184
sessions
History
Date
Time
Result
Not Attempted Yet
The Quidditch Trillenium Stadium has 8 entrances. What is the probability that 4 wizards entering the stadium, will each choose a different entrance ?
A. 35/2048
B. 105/2048
C. 35/256
D. 105/256
E. 105/128
A. 35/2048
B. 105/2048
C. 35/256
D. 105/256
E. 105/128
Attachment:
Stadium.png
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03 Oct 2022, 02:28
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[quote="Bunuel"]The Quidditch Trillenium Stadium has 8 entrances. What is the probability that 4 wizards entering the stadium, will each choose a different entrance ?
A. 35/2048
B. 105/2048
C. 35/256
D. 105/256
E. 105/128
Probability that first player chooses any one gate = 1/8
Probability that two player chooses any gate other than the gate chosen by player 1 = 7/8
Probability that three player chooses any gate other than the gates chosen by player 1 & 2 = 6/8
Probability that four player chooses any gate other than the gate chosen by player 1, 2 & 3 = 5/8
1/8 x 7/8 x 6/8 x 5/8 = 210/2^12 = 105/2^11 = 105/2048
Maybe......
A. 35/2048
B. 105/2048
C. 35/256
D. 105/256
E. 105/128
Probability that first player chooses any one gate = 1/8
Probability that two player chooses any gate other than the gate chosen by player 1 = 7/8
Probability that three player chooses any gate other than the gates chosen by player 1 & 2 = 6/8
Probability that four player chooses any gate other than the gate chosen by player 1, 2 & 3 = 5/8
1/8 x 7/8 x 6/8 x 5/8 = 210/2^12 = 105/2^11 = 105/2048
Maybe......
03 Oct 2022, 04:52
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OA D
8 entrances 4 wizards entering
Total ways in which 4 guys can enter is 8^4 since each have 8 options to chose from.
Condition: Each wizard enters from a different entrance
So Wizard A has 8 options B has 7 because he can't choose the one that A did
So probability= 8*7*6*5/8^4=105/256
8 entrances 4 wizards entering
Total ways in which 4 guys can enter is 8^4 since each have 8 options to chose from.
Condition: Each wizard enters from a different entrance
So Wizard A has 8 options B has 7 because he can't choose the one that A did
So probability= 8*7*6*5/8^4=105/256
