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PS1
10=S2=a1+a2=2a1+d..(1)
21=S3=S2+a3=10+a1+2d
Ie a1+2d=11..(2)
Solving 1 and 2 ,
a1=3, d=4
ax=a1+( x-1)d=4x-1
Now 9|ax meaning 4x-1=9k
I.e x=9k+1/4 =7 for k=3 which is the minimum of k
agnee
So C is the correct option.
