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Bunuel
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Sigh like with all the Probability and combination questions the answer seems so obvious after youve got it wrong once .

Got it wrong on the first try picked C

2nd try -

Total no of shoes = 6* 2 = 12
No of pink shoes = 2*2 = 4

Probability of picking a matching pair = prob of picking a pink shoe * Prob of picking the shoe that forms the pair for picked shoe
= 4/12 * 1/11 (as only one of the remaing 11 will form a pair with the first shoe)
= 1/33
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Given: Harry has 6 different pairs of shoes, 2 pairs are pink.
Asked: If he selects 2 individual shoes at random and without replacement, what is the probability that he selects a matching pink pair ?

Total shoes = 6*2 = 12
Pink shoes pairs = 2

The probability that he selects a matching pink pair = 2C1/12C2 = 2/66 = 1/33

IMO D
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Harry has 6 different pairs of shoes, 2 pairs are pink. If he selects 2 individual shoes at random and without replacement, what is the probability that he selects a matching pink pair ?

A. 1/6
B. 1/9
C. 1/11
D. 1/33
E. 1/36

Total possible selections = \(^{12}C_2\) = 66

Number of favorable outcomes = 2 (i.e. one for each pair)

Required Probability = \(\frac{2}{66}\) = \(\frac{1}{33}\)

Option D
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why can't we do (4C1 * 1)/12C2 which gives 2/33 ?
where am i going wrong? kindly help.
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abcd1234!!
Harry has 6 different pairs of shoes, 2 pairs are pink. If he selects 2 individual shoes at random and without replacement, what is the probability that he selects a matching pink pair ?

A. 1/6
B. 1/9
C. 1/11
D. 1/33
E. 1/36

why can't we do (4C1 * 1)/12C2 which gives 2/33 ?
where am i going wrong? kindly help.


In the denominator, you have the number of different pairs possible from 12 shoes. However, in the numerator, it should be 2C1, representing the number of ways to select 1 matching pink pair from the 2 available pairs (either P1_Left and P1_Right OR P2_Left and P2_Right).
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Bunuel KarishmaB what is question told that 2 pair pink color shoes is identical to each other expect the left and right shoes!! what will be the probability of selecting a perfect pink color shoe pair?
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Vibhatu
Bunuel KarishmaB what is question told that 2 pair pink color shoes is identical to each other expect the left and right shoes!! what will be the probability of selecting a perfect pink color shoe pair?
Then the probability of the second shoe will simply become 2/11 both either of the two pinks of the other foot will work since both pairs are identical.
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gmatophobia


Total possible selections = \(^{12}C_2\) = 66

Number of favorable outcomes = 2 (i.e. one for each pair)

Required Probability = \(\frac{2}{66}\) = \(\frac{1}{33}\)

Option D

Hi gmatophobia, I used combination method as well but I got it wrong at this part:

Number of favorable outcomes = 2 (i.e. one for each pair)

In my understanding, number of favourable outcomes will be:
4C1 (choose 1 shoe out of 4 pink shoes) x 1 (only 1 option that will pair with the selected shoe)

Can you please help me to understand why did you use 2C1 when there are 4 available options to choose from?

Thank you in advance 🙏
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