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After we get -5 and 3 as our solution, do we substitute this back into the original equation?
Mukulkumar19
Which of the following are roots of an equation \((x^{-2})+(2x^{-1})-15=0\)?
A. 1/5 and -1/3
B. -1/5 and 1/3
C. 1/5 and 1/3
D. -1/5 and -1/3
E. -5/2 and -1/3

To solve this let's assume x^-1 = a, hence x^-2 becomes a^2 now solve for a. We will get -5 and 3 as solution. Put it in our assumption and the answer will be -1/5 and 1/3 hence B.

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We need to find the value of x. After getting a = -5 or a = 3, we substitute these values into \(x^{-1} = a\) to find that x = -1/5 or x = 1/3.
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Assume x^-1 = a, hence x^-2 becomes a^2 now solve for a. We will get -5 and 3 as solution. Put it and the answer will be -1/5 and 1/3 hence B.
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