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1/a△(1/b△1/c)
=1/a△[1/bc(1/c+1/b)]
=1/a△[1/(b+c)]
=(1/a(b+c))/(1/a+1/(b+c))
=1/(a+b+c)

Hence C
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\(x△y = \frac{xy}{x + y}\) and we need to find the value of \(\frac{1}{a}△(\frac{1}{b}△\frac{1}{c})\) ?

\(\frac{1}{b}△\frac{1}{c}\) = \(\frac{\frac{1}{b} * \frac{1}{c}}{ \frac{1}{b} + \frac{1}{c}}\) = \(\frac{\frac{1}{bc}}{\frac{b+c}{bc}}\) = \(\frac{1}{b+c}\)

Similarly, \(\frac{1}{a}\) △ \((\frac{1}{b}△\frac{1}{c})\) = \(\frac{1 }{ a + b + c}\)

So, Answer will be C
Hope it helps!

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I wonder if this belongs in the sub-500 difficulty level.
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Khwarizmi
I wonder if this belongs in the sub-500 difficulty level.

We do not assign the difficulty level manually. The difficulty level of a question on the site is determined automatically based on various parameters collected from users' attempts, such as the percentage of correct answers and the time taken to answer the question. You can find the difficulty level of a question and its related statistics in the first post. So, the difficulty level of this question is Sub 500 Level based on the timer attempts from the users.
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