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11 Sep 2023, 01:30
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
57% (01:30) correct
43%
(01:26)
wrong
based on 49
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Not Attempted Yet
Is \(2x > x^2\) ?
(1) \(0 ≤ x^2 ≤ 9\)
(2) x is an odd prime integer.
(1) \(0 ≤ x^2 ≤ 9\)
(2) x is an odd prime integer.
11 Sep 2023, 05:18
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(1) \(0≤x^2≤9\)
so |x|≤3 and -3 ≤ x ≤ 3
if x= -1/-2.. , 2x< X^2
if x= 1 , 2x >x^2
Not Sufficient
(2) x is an odd prime integer
so x= 3,5,7 ......
clearly for all these 2x < x^2
So OPTION B
so |x|≤3 and -3 ≤ x ≤ 3
if x= -1/-2.. , 2x< X^2
if x= 1 , 2x >x^2
Not Sufficient
(2) x is an odd prime integer
so x= 3,5,7 ......
clearly for all these 2x < x^2
So OPTION B
15 Sep 2023, 07:07
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Is 2x > x^2?
1) 0 ≤ x^2 ≤ 9
when you take the root of x^2 it becomes |x|, so 0 ≤ |x| ≤ 3. Test 2 cases quickly, where x = 0 and 1
x = 0, is 0 > 0? No
x = 1, is 2 > 1? Yes
Since we got 2 different answer choices, eliminate A
2) x can be 2, 3, 5, 7, 11 .....
No need to do some calculations, the answer will always be no
x = 2, 4 > 4? No
x = 3, 6 > 9? No
x = 5, 10 > 25? No
Answer B
1) 0 ≤ x^2 ≤ 9
when you take the root of x^2 it becomes |x|, so 0 ≤ |x| ≤ 3. Test 2 cases quickly, where x = 0 and 1
x = 0, is 0 > 0? No
x = 1, is 2 > 1? Yes
Since we got 2 different answer choices, eliminate A
2) x can be 2, 3, 5, 7, 11 .....
No need to do some calculations, the answer will always be no
x = 2, 4 > 4? No
x = 3, 6 > 9? No
x = 5, 10 > 25? No
Answer B
