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Problem type overlapping set,­
lets assume number of E1 = exactly 1 colored pair, E2 = exactly 2 colored pair, E3 = exactly 3 colored pair,
Given - A sock drawer contains 36 pairs of socks, which are colored white, brown, or black, in some combination as follows:

• 5 pairs are colored with all three colors; = E3 = 5
• 25 pairs have some white;
• 28 pairs have some brown;
• 20 pairs have some black.

Total pair of socks = 36 = E1 + E2 + E3,
E1 + E2 = 36 - 5 = 31 --- Eq1
and, E1 + 2E2 + 3E3 = 25 + 28 + 20 = 73
E1 + 2E2 = 73 - 15 = 58 ---- Eq2
on solving E2 = 27
E1 = 4
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We know there are 36 pairs of socks

total 'colors' = 25 + 28 + 20 = 73

If 5 socks have all 3 colors, we know 5 pairs are counted in all 3 buckets, and we should de-duplicate by subtracting 5 * 2 = 10 - so we get 63 pairs...

But wait! this is much more than our total of 36 socks. So we need to find how many are still double counted. If a sock has 2 colors it is counted twice in our 63 color total, so to get the number of 2-color pairs we can do total colors - total socks = 63 - 36 = 27 - we know 27 pairs have 2 colors, and that gives us our answer for that part.

For the number of 1 color socks, we can do total - 3 color - 2 color or 36 - 27 - 5 = 36 - 32 = 4 pairs!

And this makes sense - if we have 73 total colors, we can do 4 + 27*2 (27 pairs w 2 colors) +5*3 (5 pairs w 3 colors) = 4 + 54 + 15 = 73
This is a good solution! ­I understand everything in here except the fact that how does subtracting the number of 2-color pairs from total socks ( 63 - 36 = 27 ) gives us the number of 2 color socks?
@KarishmaB @Bunuel Can you please explain this? I'm also curious how one would solve this using Venn diagrams, if possible at all.­
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­from figure, we can write that
73-2(x+y+z)+(x+y+z)+5 = 36
(x+y+z) = 27 (2 colored socks)

for one colored socks
(20-x-y)+(23-x-z)+(15-y-z) = 58-2*27 = 4
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Akshaynandurkar
­from figure, we can write that
73-2(x+y+z)+(x+y+z)+5 = 36
(x+y+z) = 27 (2 colored socks)

for one colored socks
(20-x-y)+(23-x-z)+(15-y-z) = 58-2*27 = 4
­Thanks! This was helpful. I tried solving this question using Venn diagram and got stuck because I took 25 as pairs with ONLY white,
28 as pairs with ONLY some brown and 20 pairs with ONLY black.
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When we add up all the individual color counts:
25 (white) + 28 (brown) + 20 (black) = 73

But we only have 36 pairs! Where did the extra 37 come from?

Here's what happens when you count this way:
- A one-color pair (say, all white) gets counted 1 time - correct!
- A two-color pair (say, white-brown) gets counted 2 times - once in white, once in brown. That's 1 extra count.
- A three-color pair gets counted 3 times - once in each color. That's 2 extra counts.

So the "overcount" of 37 comes from:

Overcount = (two-color pairs) x 1 + (three-color pairs) x 2

We know three-color = 5, so:

37 = (two-color) + 5 x 2
37 = (two-color) + 10
Two-color = 27

And since total = one-color + two-color + three-color:
36 = one-color + 27 + 5
One-color = 4

Answer: One color = 4, Two colors = 27

Regarding Venn Diagrams:
Yes, you can use a Venn diagram with 3 overlapping circles (White, Brown, Black). The center region where all three overlap = 5. You'd then need to find the other 7 regions. However, the overcounting method above is faster since we don't need to find each individual region - we just need the totals for "exactly one color" and "exactly two colors."

Think of it this way: The overcount tells us how many times we "double-dipped" when adding. Each two-color pair was dipped twice, each three-color pair was dipped three times. The extra dips = 37, and working backwards gives us the answer.

siddhantvarma

This is a good solution! ­I understand everything in here except the fact that how does subtracting the number of 2-color pairs from total socks ( 63 - 36 = 27 ) gives us the number of 2 color socks?
@KarishmaB @Bunuel Can you please explain this? I'm also curious how one would solve this using Venn diagrams, if possible at all.­
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