What is the sum of all multiples of 3 between 1 and 200?

Question

A. 3,300
B. 6,600
C. 6,633
D. 10,100
E. 20,100

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cdrectenwald · Accepted Answer

I got c:

first term: 3
last term: 198
# number of terms: (198-3)/3 + 1= 66
sum: 66/2 X (3+198) = 6633

Maheshkv · Answer

first number = 3, last number = 198

arithmetic progression with common diff of 3, hence sum would be (66*(3+198))/2 =6633

Sum of n terms of AP = (number of terms * (first + last term))/2

Abhishek009 · Answer

3 + 6 + 9.......... + 195 + 198

= 3(1 + 2 + 3...........63 + 64 + 65 + 66)

= 3(\frac{66*67}{2})

= 6633 , Answer must be (C)

VivekSri · Answer

OA is C

Posted from my mobile device

getsetfly · Answer

Hey, can you please tell me when we need to do +1 to find the number of terms and when not.....thanks!!

Bunuel · Answer

Number \ of \ multiples \ of \ x \ in \ the \ range =

=\frac{Last \ multiple \ of \ x \ in \ the \ range \ - \ First \ multiple \ of \ x \ in \ the \ range}{x}+1 .

Example 1:  how many multiples of 5 are there between -7 and 35, not inclusive?

Last multiple of 5  IN  the range is 30;
First multiple of 5  IN  the range is -5;

\frac{30-(-5)}{5}+1=8 .

Example 2:  How many multiples of 4 are there between 12 and 96, inclusive?
 \frac{96-12}{4}+1=22 .

Example 3: 
How many multiples of 7 are there between -28 and -1, not inclusive?
Last multiple of 7  IN  the range is -7;
First multiple of 7  IN  the range is -21;

\frac{-7-(-21)}{7}+1=3 .

Hope it helps.

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What is the sum of all multiples of 3 between 1 and 200?

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What is the sum of all multiples of 3 between 1 and 200?

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