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08 Jan 2024, 02:30
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
81% (01:44) correct
19%
(02:10)
wrong
based on 240
sessions
History
Date
Time
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Not Attempted Yet
What is the sum of all multiples of 3 between 1 and 200?
A. 3,300
B. 6,600
C. 6,633
D. 10,100
E. 20,100
A. 3,300
B. 6,600
C. 6,633
D. 10,100
E. 20,100
08 Jan 2024, 03:58
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I got c:
first term: 3
last term: 198
# number of terms: (198-3)/3 + 1= 66
sum: 66/2 X (3+198) = 6633
first term: 3
last term: 198
# number of terms: (198-3)/3 + 1= 66
sum: 66/2 X (3+198) = 6633
General Discussion
08 Jan 2024, 04:34
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first number = 3, last number = 198
arithmetic progression with common diff of 3, hence sum would be (66*(3+198))/2 =6633
Sum of n terms of AP = (number of terms * (first + last term))/2
arithmetic progression with common diff of 3, hence sum would be (66*(3+198))/2 =6633
Sum of n terms of AP = (number of terms * (first + last term))/2
