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805+ (Hard)|   Math Related|               
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guddo
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Sans8
Given,
More than half of the employees at Company A have salaries below the average for Company B.
Hence, the median salary would also be less than the average for company B.

Now, looking through options
if,
>> If the average salary at Company B is greater than 100,000 AED
Then, median can be anything either greater or less than or equals 100,000 AED.
Hence no option satisfying it. In a similar way if we check logically through all options
Only less than 100,000 AED satisfies.

If the average salary at Company B is less than 100,000 AED than median will also be less that 100,000AED

chetan2u I solved it through logic is there any other way for it to be solved?
KarishmaB chetan2u MartyMurray Bunuel bb

Can someone please explain why this is not the answer? I applied the same reason to arrive at this solution.

Option 1 - greater than 100,000 AED
Option 2 - less than 100,000 AED
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Does this not answer your question?

Prove that it’s not true:

If the average salary at Company B is greater than 100,000 AED, Then, median can be anything either greater or less than or equals 100,000 AED.
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Sans8
Given,
More than half of the employees at Company A have salaries below the average for Company B.
Hence, the median salary would also be less than the average for company B.

Now, looking through options
if,
>> If the average salary at Company B is greater than 100,000 AED
Then, median can be anything either greater or less than or equals 100,000 AED.
Hence no option satisfying it. In a similar way if we check logically through all options
Only less than 100,000 AED satisfies.

If the average salary at Company B is less than 100,000 AED than median will also be less that 100,000AED

chetan2u I solved it through logic is there any other way for it to be solved?
KarishmaB chetan2u MartyMurray Bunuel bb

Can someone please explain why this is not the answer? I applied the same reason to arrive at this solution.

Option 1 - greater than 100,000 AED
Option 2 - less than 100,000 AED

This is quite an interesting question and BB has given you great food for thought.

The way I think about it is this:
From the argument I can make out that median of A is less than mean of B and that is all.

So if mean of B is less than 100k, then median of A is less than 100k too. - Definitely true

If mean of B is more than 100k (say it is 105k), median of A could be more than 110k (say it could be 102k) or it could be equal to 100k or it could be less than 100k (say 90k). Anything is possible.

Hence the answer is less than 100k for both.

It is so simple and yet so hard!! I visualise the number line and think in terms of left of 100k or right of 100k.
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Relatively simple question. This is one of the few DI questions that don't have complex wordings.

[more than half of the employees at Company A have salaries below the average for Company B.] --> This sentence tells us that the median at company A is the salary of one of these guys.

Therefore, if we know the mean(B) < X (a certain amount), then according to the prompt, we know more than half of A has a salary less than < X. Thus, the median is also a number that is less than X.
Note that if mean(B) > X (a certain amount), we cannot infer what is the range of those low-earners in A. Let's say that an average employee in B earn more than $100K/year, we cannot say whether those low-earners in A earn >100K, 100K, or <100K.

When I was doing this question, I was pre-thinking of [equal to 110,000 AED] for blank 1; and [less than 110K] for blank 2. But sadly they don't have that option for blank 2 :(
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Please someone correct me if i am wrong -
Lesson learned that in TPA, there could be many one-to-many pairs that can fit as solution, however, we need to select that ONE pair that is strictly one-to-one.
In this case:
if 1- less than 100K , only answer 2 can have is -less than 100K

if we choose any other option for 1, we can have many option which can be true for 2.
Like if 1- greater than 100K , 2 can be - Less than 100K , Equal to 110K etc. which cant be right.
guddo
Companies A and B are part of the same industry and are located in the same city. For Company A, the average (arithmetic mean) salary of its employees, in United Arab Emirates dirhams (AED), is 10,000 AED higher than that for Company B. However, more than half of the employees at Company A have salaries below the average for Company B.

Statement: If the average salary at Company B is ___1___, then the median salary at Company A is ___2___.

Select for 1 and for 2 the options that complete the statement so that it most accurately reflects the information provided. Make only two selections, one in each column.­

ID: 700200

If this question felt shaky, try an adaptive mini quiz of similar problems in GMAT Club Forum Quiz →. Free plan gives 5 questions per day.
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tryorcry
Please someone correct me if i am wrong -
Lesson learned that in TPA, there could be many one-to-many pairs that can fit as solution, however, we need to select that ONE pair that is strictly one-to-one.
In this case:
if 1- less than 100K , only answer 2 can have is -less than 100K

if we choose any other option for 1, we can have many option which can be true for 2.
Like if 1- greater than 100K , 2 can be - Less than 100K , Equal to 110K etc. which cant be right.


Your “one to one” takeaway is right, but the reason is simpler:

We are told: more than half of Company A’s employees earn below Company B’s average. That means the median at Company A must be below Company B’s average (because the median is the point where at least half are at or below it).

So whatever you pick for 1 (Company B’s average), 2 must be “less than that value.” Among the choices, the only time you can force a single specific choice for 2 is when 1 is “less than 100,000 AED,” because then the only compatible option for 2 is also “less than 100,000 AED.” For the other 1 options, several 2 options could still be below B’s average, so they do not give a unique pair.
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