Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2301:30 AM EDT
-02:30 AM EDT
Struggling with GMAT Verbal as a non-native speaker? Harsh improved his score from 595 to 695 in just 45 days—and scored a 99 %ile in Verbal (V88)! Learn how smart strategy, clarity, and guided prep helped him gain 100 points.
Apr 2308:00 PM PDT
-09:00 PM PDT
Video explanations + diagnosis of 10 weakest areas + 150+ short videos + study plan!
Apr 2512:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
05 Sep 2024, 03:14
Kudos
Bookmarks
The repair required less than half the average time to complete: True for all chips with spidering
The chip diameter was larger than the median chip diameter.: False for at least one chip with spidering
The insurance reimbursement was greater than or equal to the median insurance reimbursement.: False for at least one chip with spidering
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
78% (02:42) correct
22%
(03:01)
wrong
based on 799
sessions
History
Date
Time
Result
Not Attempted Yet
On a recent workday, a technician repaired one chip—a small area from which a fragment of glass had been broken—in the windshield of each of 9 automobiles. For each automobile, the table indicates the chip’s diameter, in millimeters (mm); whether the chip was accompanied by spidering, which is a pattern of cracks radiating out from the chip; the volume, in milliliters (mL), of sealant used to repair the chip and any accompanying spidering; the time, in hours (h), to complete the repair; and the insurance reimbursement, which is the amount, in US dollars (US$), that was reimbursed by insurance.
For each of the following, select True for all chips with spidering if the given information indicates that the statement is true for each of the 9 chips that was accompanied by spidering. Otherwise, select False for at least one chip with spidering.
| Automobile | Chip diameter (mm) | Spidering? (yes/no) | Volume of sealant used (mL) | Time to complete repair (h) | Insurance reimbursement (US$) |
|---|---|---|---|---|---|
| 1 | 17 | yes | 5 | 0.25 | 45 |
| 2 | 8 | no | 2 | 0.75 | 52 |
| 3 | 24 | yes | 5 | 0.25 | 70 |
| 4 | 5 | no | 1 | 1 | 70 |
| 5 | 17 | yes | 4 | 0.25 | 52 |
| 6 | 17 | no | 3 | 0.75 | 45 |
| 7 | 12 | no | 2 | 1 | 70 |
| 8 | 10 | no | 2 | 0.5 | 70 |
| 9 | 6 | yes | 6 | 0.25 | 52 |
| Average (arithmetic mean) | 12.89 | - | 3.33 | 0.56 | 58.44 |
For each of the following, select True for all chips with spidering if the given information indicates that the statement is true for each of the 9 chips that was accompanied by spidering. Otherwise, select False for at least one chip with spidering.
| True for all chips with spidering | False for at least one chip with spidering | |
| The repair required less than half the average time to complete | ||
| The chip diameter was larger than the median chip diameter. | ||
| The insurance reimbursement was greater than or equal to the median insurance reimbursement. |
ShowHide Answer
Official Answer
The repair required less than half the average time to complete: True for all chips with spidering
The chip diameter was larger than the median chip diameter.: False for at least one chip with spidering
The insurance reimbursement was greater than or equal to the median insurance reimbursement.: False for at least one chip with spidering
Trying to understand why the right answer is right?
GMAT Club Tests explanations walk through concepts, shortcuts, and common traps on many questions.
See how →
08 Sep 2024, 01:23
Kudos
Bookmarks
The best way to solve these questions is just have a glance of what is given
Variables and any combined aggregated values
- Variables - Diameter, Volume, Spidering (yes/no), Insurance reibursement
- Aggregated Values - Average
Lets go on option
Who Q is based on spidering - so lets quickly sort the table and any where there is mentioned NO spidering just move on.
Now,
We have 4 spidering options - lazer focus there.
A. Mean is already given in table so we dont need to calculate - great news. For all 4 spidering the time is less than half of mean (0.56/2). Click yes for all
B. Calculate median of all values in column diameter - 5,6,8,10,12,17,17,17,24 - Median is 12. One spidering one doesnt has it greater than 12 but rest do so choose Atleast one column
C. Calculate median of all values in column insurance - 45,45,52,52,52,70,70,70,70 - Median is 52. One spidering one doesnt has it greater than 52 but rest do so choose Atleast one column
Variables and any combined aggregated values
- Variables - Diameter, Volume, Spidering (yes/no), Insurance reibursement
- Aggregated Values - Average
Lets go on option
Who Q is based on spidering - so lets quickly sort the table and any where there is mentioned NO spidering just move on.
Now,
We have 4 spidering options - lazer focus there.
A. Mean is already given in table so we dont need to calculate - great news. For all 4 spidering the time is less than half of mean (0.56/2). Click yes for all
B. Calculate median of all values in column diameter - 5,6,8,10,12,17,17,17,24 - Median is 12. One spidering one doesnt has it greater than 12 but rest do so choose Atleast one column
C. Calculate median of all values in column insurance - 45,45,52,52,52,70,70,70,70 - Median is 52. One spidering one doesnt has it greater than 52 but rest do so choose Atleast one column
23 Sep 2024, 03:37
Kudos
Bookmarks
im not able to understand the question can anbody explain this
