x and y are integers. If x + 1 0 and xy 0, which of the following

Question

x and y are integers. If x + 1 > 0 and xy > 0, which of the following must be true? A. y > 0 B. y < 0 C. y > x D. y < x E. None of these

skasmani · Answer

X+1>0
Even if x=0, total is 1

Xy>0
Y can’t be 0
Y can’t be -ve
Y>x is maybe true
Y<x can’t be true in my assumption

Y has to be atleast 1
Hence A

If there’s a better approach, please share

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btsaami · Answer

x + 1 > 0 i.e. x can either be 0 or positive integer.
and xy > 0 x= 0 not possible. Second, x is positive, y also has to be positive which is satisfied by option A.

Just for sake of verification, we can go through other option.

B incorrect as described above.
C and D no such condition is mentioned.

JL77 · Answer

I'm confused as to why E isn't the answer because based on the statement x+1>0, x can equal a negative number greater than -1 (-0.2, -0.5, etc). If x is negative then Y can also be negative to make the statement xy>0 true.

Bunuel · Answer

Pay attention to the highlighted part in the question. Given that x is an integer, x > -1, and xy > 0, x can be 1, 2, 3, and so on.

pierjoejoe · Answer

x and y are integers,

condition 1 --> x+1 > 0 --> means that x is greater than -1 --> thus x will be zero or more
condition 2 --> x*y > 0 --> means that either x > 0 and y > 0, or x<0 and y<0, furthermore, we know that neither x nor y are zero

from condition 1 we know that x is at least 0, meaning that, given the second condition, we are fore sure in the case where both x and y are positive. thus A

as for the others
A. y > 0 --> OK
B. y < 0 --> not possible since x*y >0 and x is greater than -1 and a INTEGER
C. y > x --> we cannot know this. We only know that x and y are positive
D. y < x --> same
E. None of these --> answer A is fine, so it cannot be E

IMO A

x and y are integers. If x + 1 > 0 and xy > 0, which of the following

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