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06 Nov 2024, 01:31
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
69% (02:18) correct
31%
(02:08)
wrong
based on 497
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AB
+BA
CDC
In the correctly worked computation above A, B, C and D represent distinct nonzero digits. What is the value of A+B+C+D
A. 14
B. 16
C. 18
D. 20
E. It cannot be determined from given information
+BA
CDC
In the correctly worked computation above A, B, C and D represent distinct nonzero digits. What is the value of A+B+C+D
A. 14
B. 16
C. 18
D. 20
E. It cannot be determined from given information
06 Nov 2024, 03:53
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C has to be 1.
Now \(A+B= 11\), so \(C\) is \(1\) and \(A+B+1 = CD\), meaning \(CD is 11+1 = 12\) (\(C=1\) and \(D=2\))
\(A+B+C+D = 11+1+2 = 14\)
I think A
- A+B can max be 17, so C would be 7 in that case, but it wont be possible to make A+B=CD when A+B=17 and CD starts with 7.
- Let's say C is 2, meaning A+B = 12, so A+B= 2D, which again is not possible since the max sum of A+B is 17, it cant go to the 20s.
- And A+B can't be a single digit too, if so there wont be a C infront of D in the given sum.
Now \(A+B= 11\), so \(C\) is \(1\) and \(A+B+1 = CD\), meaning \(CD is 11+1 = 12\) (\(C=1\) and \(D=2\))
\(A+B+C+D = 11+1+2 = 14\)
I think A
06 Nov 2024, 04:58
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hey, i started with the same reasoning, c has to be one (because c can't be 0 and the sum can be maximum for 2 digits number 198).
Then i realised that because c is 1, the sum of A+B as to be more then 10, also because, unit and decimal sum is the almost the same (A+B,B+A), D is the same result compare to the unit sum, but with +1 (because unit digits sum are more then 9)
So d is 2
now, we know that C=1, D=2 and A+B equal 11 (because of the sum's unit)
it gives you 14, A
Then i realised that because c is 1, the sum of A+B as to be more then 10, also because, unit and decimal sum is the almost the same (A+B,B+A), D is the same result compare to the unit sum, but with +1 (because unit digits sum are more then 9)
So d is 2
now, we know that C=1, D=2 and A+B equal 11 (because of the sum's unit)
it gives you 14, A
