We are counting **two-digit numbers** where the two digits are **different**.
Examples that work:
* **12** ✅
* **47** ✅
* **90** ✅
Examples that do **not** work:
* **11** ❌ (both digits are the same)
* **55** ❌
* **99** ❌
Think of a two-digit number as having:
```text id="j4p4rq"
[Tens digit] [Ones digit]
```
### Step 1: Choose the first digit
The first digit cannot be **0**, because then it would not be a two-digit number.
So we can choose:
```text id="2m9o5e"
1, 2, 3, 4, 5, 6, 7, 8, or 9
```
That gives us **9 choices**.
### Step 2: Choose the second digit
There are **10 possible digits**:
```text id="v6gqcy"
0, 1, 2, 3, 4, 5, 6, 7, 8, 9
```
But the second digit **cannot equal the first digit**.
So:
```text id="hmf2jp"
10 − 1 = 9 choices
```
### Step 3: Multiply
For every one of the **9 choices** for the first digit, there are **9 choices** for the second digit:
```text id="hbrdf4"
9 × 9 = 81
```
✅ **Answer: (B) 81**
Another quick way:
There are **90 two-digit numbers** total:
```text id="i7hyy7"
10 through 99 = 90 numbers
```
There are **9 numbers with matching digits**:
```text id="v0sw79"
11, 22, 33, 44, 55, 66, 77, 88, 99
```
So:
```text id="ddf3ta"
90 − 9 = 81
```
Therefore, **81 two-digit integers have different digits**.