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Bunuel
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If X and Y are positive integers then Max of X - Min of Y will satisfy the condition.
X-Y = Max of X i.e. 8 - Min of Y i.e. 1
= 7 (satisfies the condition as 8+1 > 10)

Hence E.
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ABCD are not must be true so E is the only one left
Bunuel
If x and y are positive integers such that (x + y) < 10, then which of the following must be true?

A) x < 8

B) x > 3

C) x >y

D) x + y = 5

E) x - y <= 7

­
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A) x<8
x<8
Counterexample: x=8, y = 1 → x + y = 9 < 10
x+y=9<10.
So not always true.

B) x > 3
Counterexample: x = 1, y = 1
So not always true.

C) x > y
Counterexample: x = 1, y = 2
So not always true.

D) x + y = 5
Many possibilities do not sum to 5.
So not true.

E) x − y ≤ 7
Largest possible value of x − y occurs when x is largest and y is smallest:

Max x is 8
Min y is 1.

Then x − y = 8 − 1 = 7

Correct answer: E
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Bunuel
If x and y are positive integers such that (x + y) < 10, then which of the following must be true?

A) x < 8

B) x > 3

C) x >y

D) x + y = 5

E) x - y <= 7

­
It’s given that x,y are positive integers ( greater than 0).

X >= 1

Y>=1

More over it’s given that (x+y) < 10

( x+y) minimum = (1+1) = 2

(x+y) maximum = 9

Let’s look into the options :

A) x < 8

This means x can take the values 7,6,5,4,3,2,1. But, as per question x can also take the value 8.

Hence, Wrong.

B) x > 3

x is a positive integer , and x can take values greater than 0. So, 1,2 also exists. Hence, Wrong.

C) x >y

(x+y) <10. Lets for time being take (x+y) = 9

y=8 and x = 1 . (y>x)

This contradicts the option. Hence, wrong.

D) x + y = 5

This can be true, but not must be true. Hence, wrong.

E) x - y <= 7

(x+y) can take the minimum value of (1+1) = 2

(x+y) < 10 , which means the max value either x or y can take is (1,8) or (8,1).

x- y = 8-1 = 7

if y increases, the value of (x-y) falls below 7.

Hence, correct.

Option E
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