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09 Dec 2025, 01:27
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x: 36
y: 16
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
40% (03:24) correct
60%
(03:34)
wrong
based on 229
sessions
History
Date
Time
Result
Not Attempted Yet
In the first round of a robotics engineering challenge, a team must earn at least 70% of the maximum possible points to qualify for the international stage. After the first round of scoring, the team had earned exactly x points, while the remaining y points were lost due to errors.
The lead engineer correctly concluded that the team did not qualify based on this score. However, if the team had avoided just one of the lost-point errors, their score would have increased enough to qualify, assuming all other factors remained the same.
Select a value for x and a value for y that are jointly consistent with the information provided. Make only two selections, one in each column.
The lead engineer correctly concluded that the team did not qualify based on this score. However, if the team had avoided just one of the lost-point errors, their score would have increased enough to qualify, assuming all other factors remained the same.
Select a value for x and a value for y that are jointly consistent with the information provided. Make only two selections, one in each column.
| x | y | |
| 12 | ||
| 16 | ||
| 24 | ||
| 28 | ||
| 32 | ||
| 36 |
ShowHide Answer
Official Answer
x: 36
y: 16
09 Dec 2025, 02:14
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Given that a team must score a minimum of 70% of the maximum points to qualify. Also the team scores x and loses out on y (which is 30% of the maximum points)
Since the team did not qualify for the international stage, it means x/y < 7/3.
Also it is given that x+1/y-1 >= 7/3.
To find values of x we need to see that x = 2y + 1/3y.
From the values we can see that if we take y = 12, then x = 24 + 4 = 28. But 28/12 = 7/3 and not less than 7/3. Hence rejected.
If we take y = 16, then x = 32 + 5.3 ~ 37. So we can say that x = 36 (from the options). Now let's check if x+1 / y-1 >= 7/3.
37+1 / 16 - 1 = 38 / 15 = 7.6 /3, which is exactly what we need.
Hence, our answer is x = 36 and y = 16.
Since the team did not qualify for the international stage, it means x/y < 7/3.
Also it is given that x+1/y-1 >= 7/3.
To find values of x we need to see that x = 2y + 1/3y.
From the values we can see that if we take y = 12, then x = 24 + 4 = 28. But 28/12 = 7/3 and not less than 7/3. Hence rejected.
If we take y = 16, then x = 32 + 5.3 ~ 37. So we can say that x = 36 (from the options). Now let's check if x+1 / y-1 >= 7/3.
37+1 / 16 - 1 = 38 / 15 = 7.6 /3, which is exactly what we need.
Hence, our answer is x = 36 and y = 16.
12 Dec 2025, 06:40
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1st Equation:
70(x+y)/100 > x
2nd Equation:
70(x+y)/100 < x+1
Solving the 2 equations we get:
(7y-10)/3 < x< 7y/3
Then putting y as 16 (from the options), we get - 34.something < x < 37.something
x -> 35, 36, 37 - out of these 36 is given in the options.
x=36
y=16
70(x+y)/100 > x
2nd Equation:
70(x+y)/100 < x+1
Solving the 2 equations we get:
(7y-10)/3 < x< 7y/3
Then putting y as 16 (from the options), we get - 34.something < x < 37.something
x -> 35, 36, 37 - out of these 36 is given in the options.
x=36
y=16
