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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
60% (01:47) correct
40%
(01:39)
wrong
based on 43
sessions
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At a water-treatment facility, a pump was used to fill an empty storage tank. If the pump operated at a constant rate throughout the process, how many minutes did it take the pump to fill the tank?
(1) If the pump’s flow rate had been 25% greater, the tank would have been filled 16 minutes sooner.
(2) If the pump’s flow rate had been 20% lower, the tank would have taken 20 minutes longer to fill.
(1) If the pump’s flow rate had been 25% greater, the tank would have been filled 16 minutes sooner.
(2) If the pump’s flow rate had been 20% lower, the tank would have taken 20 minutes longer to fill.
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30 Apr 2026, 03:30
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GMAT Club Official Solution:
At a water-treatment facility, a pump was used to fill an empty storage tank. If the pump operated at a constant rate throughout the process, how many minutes did it take the pump to fill the tank?
(1) If the pump’s flow rate had been 25% greater, the tank would have been filled 16 minutes sooner.
Let the actual time be t minutes.
If the pump’s flow rate had been 25% greater, the new rate would have been 1.25 times the actual rate. So the filling time would have been t/1.25 = 0.8t.
The statement says this would have been 16 minutes sooner, so:
t - 0.8t = 16
0.2t = 16
t = 80
Sufficient.
(2) If the pump’s flow rate had been 20% lower, the tank would have taken 20 minutes longer to fill.
Again let the actual time be t minutes.
If the pump’s flow rate had been 20% lower, the new rate would have been 0.8 times the actual rate. So the filling time would have been t/0.8 = 1.25t.
The statement says this would have increased the time by 20 minutes, so:
1.25t - t = 20
0.25t = 20
t = 80
Sufficient.
Answer: D.
At a water-treatment facility, a pump was used to fill an empty storage tank. If the pump operated at a constant rate throughout the process, how many minutes did it take the pump to fill the tank?
(1) If the pump’s flow rate had been 25% greater, the tank would have been filled 16 minutes sooner.
Let the actual time be t minutes.
If the pump’s flow rate had been 25% greater, the new rate would have been 1.25 times the actual rate. So the filling time would have been t/1.25 = 0.8t.
The statement says this would have been 16 minutes sooner, so:
t - 0.8t = 16
0.2t = 16
t = 80
Sufficient.
(2) If the pump’s flow rate had been 20% lower, the tank would have taken 20 minutes longer to fill.
Again let the actual time be t minutes.
If the pump’s flow rate had been 20% lower, the new rate would have been 0.8 times the actual rate. So the filling time would have been t/0.8 = 1.25t.
The statement says this would have increased the time by 20 minutes, so:
1.25t - t = 20
0.25t = 20
t = 80
Sufficient.
Answer: D.
General Discussion
23 Apr 2026, 22:56
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IMO D.
Statement 1:
This is typical of distance/rate problem.
When one goes up by some amount in ratio form, other comes down by its reciprocal.
The decrease in the ratio is the sooner value:
If flow rate = 5/4x ,Time taken = 4/5x.
1/5x = 16.
x=80.
SUFFICIENT.
Statement 2:
Similar steps as above and we get
x = 80 again.
SUFFICIENT.
Answer: Option D
Statement 1:
This is typical of distance/rate problem.
When one goes up by some amount in ratio form, other comes down by its reciprocal.
The decrease in the ratio is the sooner value:
If flow rate = 5/4x ,Time taken = 4/5x.
1/5x = 16.
x=80.
SUFFICIENT.
Statement 2:
Similar steps as above and we get
x = 80 again.
SUFFICIENT.
Answer: Option D
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