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Let the actual filling time be T minutes.
Let tank volume = V and pump rate = R.
So, V = RT

Statement (1)
New rate = 1.25R
New time = V / 1.25R = RT / 1.25R = T / 1.25 = 0.8T
T - 0.8T = 16
0.2T = 16
T = 80
Statement (1) is sufficient.

Statement (2)
New rate = 0.8R
New time = V / 0.8R = RT / 0.8R = 1.25T
1.25T - T = 20
0.25T = 20
T = 80
Statement (2) is sufficient.

Ans D

Bunuel
At a water-treatment facility, a pump was used to fill an empty storage tank. If the pump operated at a constant rate throughout the process, how many minutes did it take the pump to fill the tank?

(1) If the pump’s flow rate had been 25% greater, the tank would have been filled 16 minutes sooner.

(2) If the pump’s flow rate had been 20% lower, the tank would have taken 20 minutes longer to fill.

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