All points (x,y) that lie below the line l, shown above, satisfy which of the following inequalities? A. y < 2x + 3
B. y < -2x + 3
C. y < -x + 3
D. y < 1/2*x + 3
E. y < -1/2*x + 3
First of all we should write the equation of the line \(l\):
We have two points: A(0,3) and B(6,0).
Equation of a line which passes through two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(\frac{y-y_1}{x-x_1}=\frac{y_1-y_2}{x_1-x_2}\)So equation of a line which passes the points A(0,3) and B(6,0) would be: \(\frac{y-3}{x-0}=\frac{3-0}{0-6}\) --> \(2y+x-6=0\) --> \(y=-\frac{1}{2}x+3\)
Points below this line satisfy the inequality: \(y<-\frac{1}{2}x+3\)
ORThe equation of line which passes through the points \(A(0,3)\) and \(B(6,0)\) can be written in the following way:
Equation of a line in point intercept form is \(y=mx+b\), where: \(m\) is the slope of the line and \(b\) is the y-intercept of the line (the value of \(y\) for \(x=0\)).
The slope of a line, \(m\), is the ratio of the "rise" divided by the "run" between two points on a line, thus \(m=\frac{y_1-y_2}{x_1-x_2}\) -->\(\frac{3-0}{0-6}=-\frac{1}{2}\) and \(b\) is the value of \(y\) when \(x=0\) --> A(
0,3) --> \(b=3\).
So the equation is \(y=-\frac{1}{2}x+3\)
Points below this line satisfy the inequality: \(y<-\frac{1}{2}x+3\).
Actually one could guess that the answer is E at the stage of calculating the slope \(m=-\frac{1}{2}\), as only answer choice E has the same slope line in it.
Answer: E.
For more please check Coordinate Geometry chapter of the Math Book (link in my signature).
Hope it's clear.