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The line will be in the form of y=mx+b
In this case we are looking for a negative m (eliminate option A and D).
Finally we are looking for a line with X intercept of 6.
So if you make y=0 for all remaining formulas you get

b) x=3/2 wrong
c) x=3 wrong
e) x=6 RIGHT

ANS = E.
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All points (x,y) that lie below the line l, satisfy which of the following inequalities?

A. y<2x+3
B. y<-2x+3
C. y<-x+3
D. y<1/2x+3
E. y<-1/2x+3
Attachment:
new_PS_Lines_E.JPG

For any given line L, if the intercepts are given, we can write the equation of the line as \(\frac {x} {x-intercept} + \frac {y} {y-intercept} -1 = 0\)

For the given line, it stands as L = \(\frac {x} {6} + \frac {y} {3} -1 = 0\) Now, notice that when the value of origin is plugged in (0,0), we get L as 0+0-1 --> L<0. Thus, the origin lies on the negative side of the given line. And, as origin lies below the given line, all the points in that region will make L<0 -->

\(\frac {x} {6} + \frac {y} {3} -1<0\) --> \(\frac {y} {3}< 1-\frac {x} {6}\) --> \(y < 3-\frac {x} {2}\)

E.
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Attachment:
Line.png
All points (x,y) that lie below the line l, shown above, satisfy which of the following inequalities?

A. y < 2x + 3
B. y < -2x + 3
C. y < -x + 3
D. y < 1/2*x + 3
E. y < -1/2*x + 3

Frankly, I did this question without any calculation. I hope my approach helps you save time.

First step:
We have equation: \(y = ax + b\) in which a is the slope of the line.
I see the line "l" passes through quadrant II and IV ==> The slope of line "l" should be negative
==> A, D are out immediately.

Second step.
We see two points, say A (6, 0) and B (0, 3) on line "l".
Let plug in one point, say A (6,0) to B, C, E ==> C is out
Let plug in the second point, say B (0,3) to D & E ==> D is out

Only E remains and is correct.

Hope it helps.

PS: You can save a lot of time by using "plug in" method
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Bumping for review and further discussion*. Get a kudos point for an alternative solution!

*New project from GMAT Club!!! Check HERE

We have X intercept as 6 and Y intercept as 3

The equation of a line having a as X intercept and b as Y intercept is \(\frac{x}{a}\) + \(\frac{y}{b}\) = 1

So the equation of the line above would be \(\frac{x}{6}\) + \(\frac{y}{3}\) = 1 ----------> Y = \(\frac{-1x}{2}\) + 3

All the points below the line would satisfy the inequality Y < \(\frac{-1x}{2}\) + 3

Hence Choice E
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Attachment:
Line.png
All points (x,y) that lie below the line l, shown above, satisfy which of the following inequalities?

A. y < 2x + 3
B. y < -2x + 3
C. y < -x + 3
D. y < 1/2*x + 3
E. y < -1/2*x + 3

As an alternative solution to this question i suggest to plug-in 0 for both x and y to find the x and y intercepts. From the graph it is clearly seen that the values of y should be less than 3 and the values of x should be less than 6 so ideally when we find the x and y intercepts should get the y<3 and x<6.

a) x=0 then y<3 this part works; y=0, x>-1,5 not our target;
b) x=0 then y<3 this part works; y=0, x<1,5 not our target;
c) x=0 then y<3 this part works; y=0, x<3 not our target;
d) x=0 then y<3 this part works; y=0, x>-6 not our target;
e) x=0 then y<3 this part works; y=0, x<6 BINGO!

E is the line in the graph satisfies y< -1/2*x + 3. This method seems timeconsuming but for those who forget the functions of slope and othe formulas this is very basic visual solution. It took just under 2 min, plus just from one glance it is seen that y<3 in all options so no need to spend time for y, just concentrate to find option which satisfies for x.

Hope that helps!
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Took me 5 seconds to figure out the answer:
When you look at this graph, you can write it right away in this form: y=mx+b
b=point on y coordinate
m=negative > decreasing
m=positive > increasing
m=-1/2 = the line goes from b point to (2,2), as the next y,x integer cross, and (4,1) as the next, and (6,0) next (basically 1 in slope means that it goes 1 down, and 2 means it goes 2 down (if slope is negative, in positive one 1 means one up, 2 means 2 right).

So just by looking at (6,0) point and b=3 you can firmly say that the line is gonna be y=-1/2x+3.

So for instance if you draw line with b=2, and slope 5/3, you will get this green line (y=5/3x+2), and if you draw line with b=2 and slope -5/3, you will get orange line (y=-5/3x+2)
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Find the equation of the line by using two given points (0,3) and (6,0).

Find slope
(0-3)/(6-0)
=-1/2

Find y intercept (when x=0): y = 3 (positive)
Thus equation is y= -x/2 + 3

Since we are finding points less than the line we say y <-x/2 + 3
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Hello from the GMAT Club BumpBot!

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