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28 May 2026, 19:00
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B
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Difficulty:
95%
(hard)
Question Stats:
48% (02:53) correct
52%
(02:21)
wrong
based on 56
sessions
History
Date
Time
Result
Not Attempted Yet
A small theater sold only adult tickets and student tickets for one afternoon show. Each adult ticket cost $18, and each student ticket cost $10. If the theater sold 45 tickets for the show, how many adult tickets were sold?
(1) The average (arithmetic mean) ticket price was greater than $14.50 but less than $15.00.
(2) The total revenue from ticket sales was greater than $655 but less than $663.
(1) The average (arithmetic mean) ticket price was greater than $14.50 but less than $15.00.
(2) The total revenue from ticket sales was greater than $655 but less than $663.
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06 Jun 2026, 01:00
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GMAT Club Official Solution:
A small theater sold only adult tickets and student tickets for one afternoon show. Each adult ticket cost $18, and each student ticket cost $10. If the theater sold 45 tickets for the show, how many adult tickets were sold?
Let A be the number of adult tickets sold. Then the number of student tickets sold was 45 - A.
The total revenue was:
18A + 10(45 - A) = 450 + 8A
The question asks for A.
(1) The average ticket price was greater than $14.50 but less than $15.00.
Since 45 tickets were sold, the total revenue was greater than:
45 * 14.50 = 652.50
and less than:
45 * 15 = 675
So:
652.50 < 450 + 8A < 675
202.50 < 8A < 225
25.something < A < 28.something
So A could be 26, 27, or 28.
Not sufficient.
(2) The total revenue from ticket sales was greater than $655 but less than $663.
So:
655 < 450 + 8A < 663
205 < 8A < 213
25.something < A < 26.something
Since A must be an integer:
A = 26
Sufficient.
Answer: B.
A small theater sold only adult tickets and student tickets for one afternoon show. Each adult ticket cost $18, and each student ticket cost $10. If the theater sold 45 tickets for the show, how many adult tickets were sold?
Let A be the number of adult tickets sold. Then the number of student tickets sold was 45 - A.
The total revenue was:
18A + 10(45 - A) = 450 + 8A
The question asks for A.
(1) The average ticket price was greater than $14.50 but less than $15.00.
Since 45 tickets were sold, the total revenue was greater than:
45 * 14.50 = 652.50
and less than:
45 * 15 = 675
So:
652.50 < 450 + 8A < 675
202.50 < 8A < 225
25.something < A < 28.something
So A could be 26, 27, or 28.
Not sufficient.
(2) The total revenue from ticket sales was greater than $655 but less than $663.
So:
655 < 450 + 8A < 663
205 < 8A < 213
25.something < A < 26.something
Since A must be an integer:
A = 26
Sufficient.
Answer: B.
General Discussion
BongBideshini
Joined: 25 May 2021
Last visit: 07 Jun 2026
Posts: 293
Given Kudos: 94
Location: India
Concentration: Entrepreneurship, Marketing
Schools: HBS '27 Stanford '27 Wharton '27 Sloan '27
GPA: 3.8
WE:Engineering (Government)
Products:
28 May 2026, 22:45
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Let:
Statement (1)
Average ticket price:
Revenue / 45
14.5 < Revenue/45 < 15
652.5 < Revenue < 675
652.5 < 8A + 450 < 675
202.5 < 8A < 225
25.3125 < A < 28.125
Insufficient.
Statement (2)
655 < 8A + 450 < 663
205 < 8A < 213
25.625 < A < 26.625
A = 26
Sufficient.
Answer: B
- Adult tickets = A
- Student tickets = 45 − A
Statement (1)
Average ticket price:
Revenue / 45
14.5 < Revenue/45 < 15
652.5 < Revenue < 675
652.5 < 8A + 450 < 675
202.5 < 8A < 225
25.3125 < A < 28.125
Insufficient.
Statement (2)
655 < 8A + 450 < 663
205 < 8A < 213
25.625 < A < 26.625
A = 26
Sufficient.
Answer: B
Bunuel
