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IMO - Answer is choice A -
SO In Q 54 Total and then said 18 of them didn't signed for Photography meaning those 18 are just ceramic then comes the part 1 if we knows 12 didn't signup for ceramic then those have 12 just photography easily we can get the both
54 = 12(P) + 18(C) + (x)
A sufficient option left A & D
Now 2 statement said directly 42 Signed Ceramics meaning just 12 with Photography and yes that could again says the same 12 + 18 + x = 54 Then maybe I have choosen wrong Answer would be D in hurry I get this wrong in my opinion.

Bunuel
At a community art festival, 54 participants signed up for photography, ceramics, or both. If 18 of these participants did not sign up for photography, how many participants signed up for both photography and ceramics?

(1) Of the 54 participants, 12 did not sign up for ceramics.
(2) Of the 54 participants, 42 signed up for ceramics.

 


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Total = 54
C only=18
neither C nor P = 0
both C & P = x

i) P only=12
12+x+18=54
x=24 sufficient

ii) C = 42
x+18 = 42 => x=24 Sufficient

Answer D
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Info given

x => participants who participated in photography
y => participants who participated in ceramics

z => participants who participated in both

Given:
54 = x+y-z
18 = y-z
z = ?

S1: x-z = 12 (we have 3 variables and 3 equations z can be calculated)
S2: y = 42 (again we have all required things z can be calculated)

Ans: Both statements alone are sufficient
Bunuel
At a community art festival, 54 participants signed up for photography, ceramics, or both. If 18 of these participants did not sign up for photography, how many participants signed up for both photography and ceramics?

(1) Of the 54 participants, 12 did not sign up for ceramics.
(2) Of the 54 participants, 42 signed up for ceramics.

 


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Total participants = 54

Let p, c , k be the number of participants for photography, ceramics and both, respectively.

Since 18 did not participate in photography, we know ceramics only=18 (there is noone who took neither as per the question)
So, p = 56-18 = 36

Statement I
photography only=12
subtracting the 'both' part from photography gives photography only
36-k = 12
so k=24.
Sufficient

Statement II
c=42
ceramics only + both = 18 +k = 42
this gives k = 24.
sufficient

Hence answer is D


Bunuel
At a community art festival, 54 participants signed up for photography, ceramics, or both. If 18 of these participants did not sign up for photography, how many participants signed up for both photography and ceramics?

(1) Of the 54 participants, 12 did not sign up for ceramics.
(2) Of the 54 participants, 42 signed up for ceramics.

 


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For this, a venn diagram approach is the easiest to understand. From the Q stem, we infer that the union of photography and ceramics is 54 (which contains everyone who signed up for either of the two or both). We also know that those who did not sign up for photography are those who only signed up for ceramics. Let's divide the venn diagram into three parts - only P, both, and only C, their respective numbers denoted by a, b and c. Union is a+b+c = 54. Also, we know that c=18. So, a+b=36. Now, we have two equations with no connection between them and need to find b. We need one more equation connecting either a and b or b and c or a and c. Let's keep this in mind and look at:
(1) this tells us that a=12 and plugging it into our equation a+b = 36, we get b = 24.
(2) this tells us that c+b = 42, so we get b = 24 (42-18).
So, each statement alone is sufficient and option D is the correct option.

Bunuel
At a community art festival, 54 participants signed up for photography, ceramics, or both. If 18 of these participants did not sign up for photography, how many participants signed up for both photography and ceramics?

(1) Of the 54 participants, 12 did not sign up for ceramics.
(2) Of the 54 participants, 42 signed up for ceramics.

 


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Given : P+C+Both= 54
18 did not sign up for photography

Find: Both=?

1) Of 54, 12 did not sign up for C.
54= (54-18)+(54-12)-Both
Both= 24
It is sufficient

2) Of 54, 42 signed up for C.
54=54-18+42-Both
Both=24
It is sufficient

D) Each alone is sufficient to answer the question
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Total Participant = 54
18 did not signed up for photogrpahy = 54-18= 36

Both = Photography+ cermics - Total


Statement 1 : 12 did not signed up for ceramics
ceramics = 54-12=42
Both= 36+42-54=24
Sufficient

Statement 2: 42 signed up for ceramics
Ceramics:42 (given)
Both = 36+42-54 = 24
Sufficient

Answer: D

Bunuel
At a community art festival, 54 participants signed up for photography, ceramics, or both. If 18 of these participants did not sign up for photography, how many participants signed up for both photography and ceramics?

(1) Of the 54 participants, 12 did not sign up for ceramics.
(2) Of the 54 participants, 42 signed up for ceramics.

 


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Let us take
A -photography only , B ceramics only, C -photography and ceramic both
so A+ B+ C =54, B=18, so we need value of C
Statement 1,
value of a is 12 so and B is 18, so we can find value of C, S1 sufficient
Statement 2
B+ C is equal to 42, B is 18, so we can easily find value of C
Sufficient
So correct, answer is option D
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What we know -

P P0. Total
C ? 18
C0 0
36 18 54

St 1-
C0 total is 12
Therefore,

P P0. Total
C ? 18
C0 12 0 12
36 18 54

Thus C total = 54-12= 42
And combined CP becomes 42-18= 24
Sufficient

St 2-

P P0. Total
C ? 18 42
C0 0
36 18 54

Since C total is told to be 42
therefore C&P together becomes = 42-18=24

Sufficient

Ans - D
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Let's organize the information:

  • Total partecipants: \(T=54\)
  • No photography means only ceramics: \(C = 18\)

Let \(P\) be the number of partecipants in photography. We have to find the number of people that partecipated in both photography and ceramics (\(CP\)).

\(T = C+P-CP\) ⭢ \(CP = C+P-T\): the missing value is \(P\).



Statement 1

They give us the value of \(P\): \( P=12\).

Sufficient


Statement 1

42 people partecipated in ceramics: \(C+CP = 42 \) ⭢ \(CP=42-C\)
Since we know that \(C=18\), we can find \(CP\).

Sufficient


Answer: D
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