Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 0710:00 AM PDT
-11:00 AM PDT
A complete walkthrough of GMAT Club’s free 12-week GMAT study plan: what you study each week, how progress and goals are tracked, how the error log works, and how your practice unlocks paid tools at no cost.
Sep 0201:00 PM EDT
-11:59 PM EDT
Take 30% off all study plans with code COURSEWORK - Expires on Monday 9/7
Sep 0410:00 AM EDT
-11:59 PM EDT
We’ve worked incredibly hard to build TTP into the best test prep experience possible, and it would mean a lot to us to win Newsweek’s 2026 Readers’ Choice Award for Best Test Prep. If TTP has helped you, we’d be incredibly grateful for your vote.- Sep 07
12:01 AM PDT
-11:59 PM PDT
On the 7th, GMAT Club Tests will be Free! Including all the Quizzes, Questions, and Tests. 12 AM - 11:59 PM PDT - Sep 09
07:00 AM PDT
-10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway - Sep 09
10:00 AM PDT
-11:00 AM PDT
Three MBA applications. Three rejections. No interview invites. A year later, Aman was admitted to Cambridge Judge, SMU, and IMD. In this episode of MBA Admit Stories, Aman shares how he rebuilt his MBA application... 
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2108:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
07 Jul 2026, 09:42
Kudos
Bookmarks
Let, P = Photography
C = Ceramics
Given,
P U C = 54 .....Eq (i)
18 didnot sign up for photographic,
P = 54 - 18 = 36 ..... Eq (ii)
We need , P intersection C, x= ?
Statement 1:
12 didn't signup for ceramics,
C = 54 - 12 = 42
Thus,
54 = 36 + 42 - x
x = 24
Sufficient
Statement 2:
42 signed up for ceramics, so
C = 42
Again,
54 = 36 + 42 - x
x = 24
Sufficient
Answer : D (Each statement alone is sufficient)
C = Ceramics
Given,
P U C = 54 .....Eq (i)
18 didnot sign up for photographic,
P = 54 - 18 = 36 ..... Eq (ii)
We need , P intersection C, x= ?
Statement 1:
12 didn't signup for ceramics,
C = 54 - 12 = 42
54 = 36 + 42 - x
x = 24
Sufficient
Statement 2:
42 signed up for ceramics, so
C = 42
Again,
54 = 36 + 42 - x
x = 24
Sufficient
Answer : D (Each statement alone is sufficient)
Bunuel
alamin8
Joined: 24 May 2025
Last visit: 05 Sep 2026
Posts: 183
Given Kudos: 32
Location: Bangladesh
Concentration: Accounting, Technology
Schools: HEC Sept '27 INSEAD Aug '27 UNC '27
GPA: 3.89
07 Jul 2026, 09:48
Kudos
Bookmarks
Total = 54
P + C + both P and C = 54 ....... (1)
Since everyone signed up, i.e., P + C + both P, C, hence if photography did not sign up, that means, it will go under both P, C too.
Hence, C = 18
We need both P & C and P alone
ST1: Out of 54, 12 did not sign up for C, meaning, they are also in both P & C.
Therefore, P = 12
Plugging the values in (1)
12 + 18 + Both = 54
Both = 54-30 = 24 (Sufficient)
ST2: Out of 54, 42 signed up for C, meaning, C + Both P&C = 42
We can again find, 18 + Both = 42; Therefore, both = 24 (Sufficient)
In both times, we get 24.
Answer is D. (Each statement alone is sufficient)
P + C + both P and C = 54 ....... (1)
Since everyone signed up, i.e., P + C + both P, C, hence if photography did not sign up, that means, it will go under both P, C too.
Hence, C = 18
We need both P & C and P alone
ST1: Out of 54, 12 did not sign up for C, meaning, they are also in both P & C.
Therefore, P = 12
Plugging the values in (1)
12 + 18 + Both = 54
Both = 54-30 = 24 (Sufficient)
ST2: Out of 54, 42 signed up for C, meaning, C + Both P&C = 42
We can again find, 18 + Both = 42; Therefore, both = 24 (Sufficient)
In both times, we get 24.
Answer is D. (Each statement alone is sufficient)
07 Jul 2026, 09:49
Kudos
Bookmarks
Total participants,54
.: photography(ph) + Ceramics (C) -both
Or, Only ph+Only C+ both
Acc to the question,
Only C=18, We need to find both
Assessing statement 1 alone, Only Ph=12
.: 18+12+Both=54, .:Both=24
.: 1 is alone sufficient, therefore, we have A & D answer choice left. B,C & E is eliminated already.
Assessing statement 2 alone,
Only C+both=42
We know only C=18
.:Both=24
Both the statement alone sufficient. Hence, D is the correct answer.
.: photography(ph) + Ceramics (C) -both
Or, Only ph+Only C+ both
Acc to the question,
Only C=18, We need to find both
Assessing statement 1 alone, Only Ph=12
.: 18+12+Both=54, .:Both=24
.: 1 is alone sufficient, therefore, we have A & D answer choice left. B,C & E is eliminated already.
Assessing statement 2 alone,
Only C+both=42
We know only C=18
.:Both=24
Both the statement alone sufficient. Hence, D is the correct answer.
Bunuel
