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GMAT Club World Cup 2026 (Day 5): A recreation center surveyed 420 mem

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Mardee

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11 Jul 2026, 06:25

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We know that,
There are 2 activities: Swimming and Cardio machine workouts
Total members = 420

Let the memebrs be divided into 4 groups
Both, Cardio only, Swimming only and Neither

We are given that,
Members who met mark for both = 160
Members who met mark for cardio only = 80
Let members who met mark for swimming only = x
Members who met mark for neither = y which we need to find out

=> x + 80 + 160 + y = 420
=> x + y = 180

We are given that, for every member who met neither activity, 5 met swimming only
=> x = 5y

=> x + y = 180
=> 5y + y = 180
=> y = 30

A. 30

redandme21

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11 Jul 2026, 06:25

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t = total
s = only swimming
c = only cardio
b = both
n = neither

t = 420
b = 160
c = 80
s = 5n

t = s + c + b + n
420 = 5n + 80 + 160 + n
6n = 180
n = 30

IMO A

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11 Jul 2026, 06:43

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	Swim 2 hour mark	Swim not met 2 hour	Total
cardio met 2 hour	160	80	240
cardio not met 2 hour	5X	??? X	180
Total			420

Given in green

So, 6X = 180

X = 30

Answer: A

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11 Jul 2026, 06:44

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There are a total of 420 people surveyed for Swimming and Cardio-machine workouts.
People who do both- 160
People who do only cardio-machine workouts- 80

For every one person that does neither, 5 people do only swimming.

We need to find ppl who do neither of the two.

Let,
people who do neither = N
For every one person that does neither, 5 do swimming.
Therefore, people who do only swimming- 5N

Total participants = People who do both + People who do neither + People who do just swimming + People who do just cardio

420=160+N+5N+80
6N=180
N=30

Ans- (A)

geocircle

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11 Jul 2026, 06:52

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Total = Only Cardio + Only Swimming + Both + Neither
420 = 80 + 5*Neither + 160 + Neither
6*Neither = 420 - 240 = 180
Neither = 30

Answer A

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11 Jul 2026, 07:11

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Total = 420

S intersection C is 160
Not S intersection C is 80
If Not S intersection Not C is x
S intersection not C is 5x

All 4 of these add to total
Hence solving we get 6x + 240 = 420
Which implies x is 30

Hence (A) is the answer

topgmat25

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11 Jul 2026, 07:11

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T = Both + OnlyC + OnlyS + N

OnlyS = 5N

420 = 160 + 80 + 5N + N
180 = 6N
N = 30

The answer is A

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11 Jul 2026, 07:14

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Bunuel

A recreation center surveyed 420 members about two activities: swimming and cardio-machine workouts. Of the members surveyed, 160 met a 2-hour-per-week mark for both activities, 80 met the mark for cardio-machine workouts but not for swimming, and for every member who met the mark for neither activity, 5 met the mark for swimming but not for cardio-machine workouts. How many of the 420 members met the 2-hour-per-week mark for neither activity?

A. 30
B. 80
C. 150
D. 180
E. 260

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Assume x be the number were marked for neither activity.

The number who were marked for swimming only is 5x.

Total members: 160 (both) + 80 (cardio only) + 5x (swimming only) + x (neither) = 420

240 + 6x = 420

6x = 180

x = 30

Option A

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11 Jul 2026, 07:21

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Given that numer of members who do both swimming and cardio - 160
cardio only - 80
Let the number of members who do neither be x.
Then swimming only = 5x
Since total number of members is 420,

160+80+6x=420
6x = 180
x=30

So 30 members met the 2-hour per week for neither activity.

Bunuel

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11 Jul 2026, 07:29

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total members = only swimming + only cardio-machine + both activities + neither

420 = 5*neither + 80 + 160 + neither

6*neither = 420 - 80 - 160 = 180
neither = 30

The correct answer is A

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11 Jul 2026, 07:32

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Both is 160
Cardio only= 80
None= x
swimming only= 5x
Total =420
160+80+x+5x=420
x=30
Ans A

Bunuel

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