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04 Jun 2017, 03:52
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jimmyjamesdonkey
Sum of two sides should be greater than third side
if AB =3? then \(AB+AC=BC\)so wrong
if \(AB=9\sqrt{3}\) then \(AC+BC<AB\)so wrong
if AB=13.5 then \(AC+BC>AB\) so correct
Answer C
11 Dec 2017, 07:33
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jimmyjamesdonkey
This problem is testing us on the triangle inequality theorem in which the sum of the lengths any two sides of a triangle MUST be greater than that of the third side. Let’s test each Roman numeral to determine which could be a possible side length of AB. Keep in mind that AC = 6 and BC = 9.
I. 3
Since 6 + 3 IS NOT greater than 9, 3 cannot be the length of side AB.
II. 9√3
9√3 is roughly equal to 9 x 1.7 = 15.3, and since 6 + 9 IS NOT greater than 15.3, 9√3 cannot be the length of side AB.
III. 13.5
Since 6 + 13.5 IS greater than 9, 13.5 + 9 IS greater than 6, and 9 + 6 IS greater than 13.5; thus, 13.5 could be the length of side AB.
Answer: C
A2MBB
Joined: 14 May 2018
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Location: United States
Concentration: Strategy, Finance
Schools: Tuck '21 (I) Yale '21 (II) CBS '21 (S)
GMAT 1: 700 Q47 V40
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WE:Consulting (Accounting)
08 Sep 2018, 08:24
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guys - the mistake a lot of ppl are making is to assume II. is 9+(3^0.5) which is not what it states.
The correct way to read this is II. is 9*(3^0.5). Which, when solved, does not satisfy the almighty triangle rules.
The correct way to read this is II. is 9*(3^0.5). Which, when solved, does not satisfy the almighty triangle rules.
