Tough and tricky 2: : GMAT Problem Solving (PS)
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# Tough and tricky 2:

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11 Oct 2009, 16:17
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Tough and tricky 2:

2. The price of a bushel of corn is currently $3.20, and the price of a peck of wheat is$5.80. The price of corn is increasing at a constant rate of 5x cents per day while the price of wheat is decreasing at a constant rate of $$\sqrt{2}$$*x-x cents per day. What is the approximate price when a bushel of corn costs the same amount as a peck of wheat?

(A) $4.50 (B)$5.10
(C) $5.30 (D)$5.50
(E) \$5.60
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Re: Tough and tricky 2: [#permalink]

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12 Oct 2009, 03:18
320 + 5x = 580 - (1.414 - 1)x

Solve to get x
= 5.6
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Re: Tough and tricky 2: [#permalink]

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12 Oct 2009, 08:44
Set of Tough & tricky questions is now combined in one thread: tough-tricky-set-of-problms-85211.html

You can continue discussions and see the solutions there.
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Re: Tough and tricky 2: [#permalink]

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03 May 2011, 22:51
5.6 indeed.solving for xd and then substituting back to 3.2 + 5x gives the value.
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Re: Tough and tricky 2: [#permalink]

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02 Dec 2012, 22:07
$$3.20 + 5xD = 5.80 - (\sqrt{2}x - x)D$$
$$3.2 + 5xD = 5.80 - \sqrt{2}xD + xD$$
$$xD = \frac{2.6}{4+\sqrt{2}}$$
$$xD = 0.49$$

The price: 3.2 + 5 (.49) = 5.65

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Re: Tough and tricky 2:   [#permalink] 02 Dec 2012, 22:07
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