guddo
Train A started from Station X toward Station Y traveling at a constant speed, and on the same day, on a parallel track, Train B started from Station Y toward Station X at a constant speed. At what time did Train A reach Station Y?
(1) The two trains met at 3:00 p.m. The distance traveled by Train A was twice the distance traveled by Train B by the time they met.
(2) The ratio between the speeds of Trains A and B is 3:5. Train B started from Station Y at 6:00 a.m.
I am not sure what to make of the question. If it is an official question and correct, then perhaps I am missing something, but I cannot say what.
Using both statements we can see that ratio of speeds is 3:5, train B started at 6:00 AM (say on 3rd July) and they met at 3:00 PM (assuming on 3rd July) so train B had travelled for 9 hrs in this time.
Ratio of distance covered by the two trains = 2:1
\(\frac{SpeedA * TimeA }{ SpeedB * TimeB} = \frac{2}{1}\)
\(\frac{3s * TimeA }{ 5s * 9} = \frac{2}{1}\)
TimeA = 30 hrs
This means that train A started 30 hrs prior to 3:00 PM which means 9:00 AM of previous day (of 2nd July). But in the question, we are given that
"Train A started from Station X toward Station Y traveling at a constant speed, and
on the same day, on a parallel track, Train B started from Station Y toward Station X at a constant speed"
and I see inconsistency in the data here.
Of course, we can just go on and ignore the highlighted to get the answer as "train A took 30 hrs to cover 2/3rd of distance and hence will take another 15 hrs to cover the remaining 1/3rd and hence we can get the time at which it will reach Y. So both statements together would be sufficient.