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The first statement is NOT sufficient because we dont know at what time the trains started. 

The second statement is NOT statement beacuse we dont know at what time the train A started.\

Together ,

A's speed = 3x
B's speed = 5x
B travelled = 5x * 9 = 45x  meter
After meeting A need to travel 45x meters at the speed of 3x.

A will take = 45x / 3x = 15 hours.

So they will meet at 3 pm + 15 hours = 6 am morning 

C is the answer.  
Kindly check  chetan2u GMATinsight KarishmaB
guddo
­Train A started from Station X toward Station Y traveling at a constant speed, and on the same day, on a parallel track, Train B started from Station Y toward Station X at a constant speed. At what time did Train A reach Station Y?

(1) The two trains met at 3:00 p.m. The distance traveled by Train A was twice the distance traveled by Train B by the time they met.

(2) The ratio between the speeds of Trains A and B is 3:5. Train B started from Station Y at 6:00 a.m.
­
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guddo
­Train A started from Station X toward Station Y traveling at a constant speed, and on the same day, on a parallel track, Train B started from Station Y toward Station X at a constant speed. At what time did Train A reach Station Y?

(1) The two trains met at 3:00 p.m. The distance traveled by Train A was twice the distance traveled by Train B by the time they met.

(2) The ratio between the speeds of Trains A and B is 3:5. Train B started from Station Y at 6:00 a.m.
­
I am not sure what to make of the question. If it is an official question and correct, then perhaps I am missing something, but I cannot say what. 

Using both statements we can see  that ratio of speeds is 3:5, train B started at 6:00 AM (say on 3rd July) and they met at 3:00 PM (assuming on 3rd July) so train B had travelled for 9 hrs in this time. 
Ratio of distance covered by the two trains = 2:1

\(\frac{SpeedA * TimeA }{ SpeedB * TimeB}  = \frac{2}{1}\)

\(\frac{3s * TimeA }{ 5s * 9}  = \frac{2}{1}\)

TimeA = 30 hrs

This means that train A started 30 hrs prior to 3:00 PM which means 9:00 AM of previous day (of 2nd July). But in the question, we are given that 
"Train A started from Station X toward Station Y traveling at a constant speed, and on the same day, on a parallel track, Train B started from Station Y toward Station X at a constant speed"
and I see inconsistency in the data here. 

Of course, we can just go on and ignore the highlighted to get the answer as "train A took 30 hrs to cover 2/3rd of distance and hence will take another 15 hrs to cover the remaining 1/3rd and hence we can get the time at which it will reach Y. So both statements together would be sufficient. 
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KarishmaB
guddo
­Train A started from Station X toward Station Y traveling at a constant speed, and on the same day, on a parallel track, Train B started from Station Y toward Station X at a constant speed. At what time did Train A reach Station Y?

(1) The two trains met at 3:00 p.m. The distance traveled by Train A was twice the distance traveled by Train B by the time they met.

(2) The ratio between the speeds of Trains A and B is 3:5. Train B started from Station Y at 6:00 a.m.
­
I am not sure what to make of the question. If it is an official question and correct, then perhaps I am missing something, but I cannot say what. 

Using both statements we can see  that ratio of speeds is 3:5, train B started at 6:00 AM (say on 3rd July) and they met at 3:00 PM (assuming on 3rd July) so train B had travelled for 9 hrs in this time. 
Ratio of distance covered by the two trains = 2:1

\(\frac{SpeedA * TimeA }{ SpeedB * TimeB}  = \frac{2}{1}\)

\(\frac{3s * TimeA }{ 5s * 9}  = \frac{2}{1}\)

TimeA = 30 hrs

This means that train A started 30 hrs prior to 3:00 PM which means 9:00 AM of previous day (of 2nd July). But in the question, we are given that 
"Train A started from Station X toward Station Y traveling at a constant speed, and on the same day, on a parallel track, Train B started from Station Y toward Station X at a constant speed"
and I see inconsistency in the data here. 

Of course, we can just go on and ignore the highlighted to get the answer as "train A took 30 hrs to cover 2/3rd of distance and hence will take another 15 hrs to cover the remaining 1/3rd and hence we can get the time at which it will reach Y. So both statements together would be sufficient. 
­
This from new OG:







 
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­Statement 1: 

­A  ==>                      <==B
(X) -----------------[MP]--------(Y)
     [        2x       ]     [    x   ]  

MP: meeting point

And we know that 2 trains meet at 18:00

==> Insufficient


Statement 2:

a: Train A's speed
b: Train B's speed

\(\frac{a}{b} = \frac{3}{5}\)

And we know train B starts from 6:00

==> Insufficient


Combined:

\(\frac{a}{b} = \frac{3}{5}\)
=> a = 3k; b = 5k

Time train A travels from meeting point till destination Y: \(\frac{x}{3k}\)

Time train B has traveled until meeting point: \(\frac{x}{5k} = 18 - 6 = 12\)

=> We can find \(\frac{x}{k}\)

=> We can find \(\frac{x}{3k}\)

=> Sufficient

=> BOTH statements TOGETHER are sufficient
 ­
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Bunuel can u pls explain this problem?
Also is it not necessary to say that both trains started at the same time?
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