Traingles

Question

if two sides of the triangle are 12 and 8,then which of the following could be the area of the traingle

I 35
II 48
III 56

A. I only
B I and II
c .I and III
d. II and III
e I II and III

Guys need the explanation also.....

piyatiwari · Answer

Are you sure its "Area" they are asking for and not "Perimeter"?

samramandy · Answer

I also feel the same that it should be perimeter and not area. But I also feel that this post should have been posted in the Quants section and not in the GMAT Experience section

BR Mandeep

krishnasty · Answer

IMO, I and II only..
Wats the OA?

abhi398 · Answer

ya the question is for area and not the perimeter.....

Sorry for posting in the wrong section..

kulki · Answer

Ans : B
i and ii only. 
the max area can be 48 or less. So it is 35 or 48

samramandy · Answer

I also feel that it should be I and II.
What's the OA??

syh244 · Answer

Area is fine.

Max area is 12*8/2 = 248. so anything equal or under 48 can be the area.

Spidy001 · Answer

area of the triangle with two known side lengths a , b = (1/2)(a*b)*sin(a,b)

(a,b) is the angle between sides a and b

area = (1/2)*8*12*sin(a,b) = 48 sin(a,b)

sin(a,b) is always between 0 and 1 inclusive. (as thats the sin range)

=> area = 48*[0,..1]

=>0<=area <=48

I and II are only possible options that satisfy the above condition.

Answer is B.

yourpal · Answer

please explain?

how you come up with max area of 48.

thanks .

Spidy001 · Answer

area = (1/2)*8*12*sin(a,b) = 48 sin(a,b)
 
maximum value of sin angle is 1. so maximum value of area in the above statement = 48*1= 48

catfreak · Answer

Agreed the max area is 1/2 * 12 * 8 * sin@ and max value of sin@ is 1 = 48 
B is the answer.

Traingles

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