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Triangle ABC is isosceles. What is the measure of angle BAC?

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Triangle ABC is isosceles. What is the measure of angle BAC? [#permalink]

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New post 07 Jan 2015, 07:36
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Tough and Tricky questions: Geometry.



Triangle ABC is isosceles. What is the measure of angle BAC?

(1) angle BCA = 40°
(2) angle ABC = 100°

Kudos for a correct solution.

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Re: Triangle ABC is isosceles. What is the measure of angle BAC? [#permalink]

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New post 07 Jan 2015, 09:12
1
Answer: B

A - <BAC can be either 100, 70 or 40, depending on which sides are equal.
B - If <ABC is 100, the remaining two angles are automatically 40 because the sum of the angles cannot be greater than 180. This makes BAC 40.
C - B on its own is sufficient.
D - Only B is sufficient.
E - Incorrect.
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Re: Triangle ABC is isosceles. What is the measure of angle BAC? [#permalink]

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New post 07 Jan 2015, 11:33
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Bunuel wrote:

Tough and Tricky questions: Geometry.



Triangle ABC is isosceles. What is the measure of angle BAC?

(1) angle BCA = 40°
(2) angle ABC = 100°

Kudos for a correct solution.



Isosceles so two sides and two angles are same

1) BCA = 40 ; remaining angles can be either 40,100 or 70,70 - Insufficient
2) ABC = 100; remaining angles should be 40,40 - Sufficient

Ans B
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Triangle ABC is isosceles. What is the measure of angle BAC? [#permalink]

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New post 09 Jan 2015, 06:23
Bunuel wrote:

Tough and Tricky questions: Geometry.



Triangle ABC is isosceles. What is the measure of angle BAC?

(1) angle BCA = 40°
(2) angle ABC = 100°

Kudos for a correct solution.


OFFICIAL SOLUTION:

We use the fact that the sum of angles in any triangle is 180°. We also use the fact that an isosceles triangle has two equal angles. Let’s denote each angle by its vertex, i.e. angle BAC is angle A, angle ACB is angle C and angle ABC is angle B.

If we use statement (1) it defines angle C = 40°. If it is NOT one of the equal angles, then the sum of the equal angles is 180° – 40° = 140°. So each one of the equal angles is 140°/2 = 70°. In this case angle A is 70°.

However, if the given angle (angle C) is one of the equal angles, then we do NOT know which one is the other equal angle. If it is angle A, then it equals 40°. If not – then angle A equals 180° – (40° + 40°) = 100°. Therefore we do NOT have a definite value of angle A. So statement (1) by itself is NOT sufficient.

Statement (2) defines angle B = 100°. It looks very similar to statement (1), but there is a major difference. Angle B can NOT be one of the equal angles. If it had been so, the sum of the angles in the triangle would have exceeded 180° (100° + 100° + one more angle). That is impossible because the sum of the angles in any triangle is always 180°.Therefore angle B is NOT one of the equal angles, but angle A is. So angle A = (180° – 100°)/2 = 40°. Statement (2) by itself is sufficient to answer the question.Statement (2) by itself is sufficient to answer the question, but statement (1) by itself is not.

The correct answer is B.
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Re: Triangle ABC is isosceles. What is the measure of angle BAC? [#permalink]

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New post 09 Jan 2015, 06:23
Bunuel wrote:
Bunuel wrote:

Tough and Tricky questions: Geometry.



Triangle ABC is isosceles. What is the measure of angle BAC?

(1) angle BCA = 40°
(2) angle ABC = 100°

Kudos for a correct solution.


We use the fact that the sum of angles in any triangle is 180°. We also use the fact that an isosceles triangle has two equal angles. Let’s denote each angle by its vertex, i.e. angle BAC is angle A, angle ACB is angle C and angle ABC is angle B.

If we use statement (1) it defines angle C = 40°. If it is NOT one of the equal angles, then the sum of the equal angles is 180° – 40° = 140°. So each one of the equal angles is 140°/2 = 70°. In this case angle A is 70°.

However, if the given angle (angle C) is one of the equal angles, then we do NOT know which one is the other equal angle. If it is angle A, then it equals 40°. If not – then angle A equals 180° – (40° + 40°) = 100°. Therefore we do NOT have a definite value of angle A. So statement (1) by itself is NOT sufficient.

Statement (2) defines angle B = 100°. It looks very similar to statement (1), but there is a major difference. Angle B can NOT be one of the equal angles. If it had been so, the sum of the angles in the triangle would have exceeded 180° (100° + 100° + one more angle). That is impossible because the sum of the angles in any triangle is always 180°.Therefore angle B is NOT one of the equal angles, but angle A is. So angle A = (180° – 100°)/2 = 40°. Statement (2) by itself is sufficient to answer the question.Statement (2) by itself is sufficient to answer the question, but statement (1) by itself is not.

The correct answer is B.


Similar question to practice: in-isosceles-triangle-rst-what-is-the-measure-of-angle-r-129378.html
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Collection of Questions:
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Re: Triangle ABC is isosceles. What is the measure of angle BAC? [#permalink]

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New post 09 Jan 2015, 20:21
Are we sure this is 600-700 level?

The triangle is isosceles, but we do not know which pair of sides or angles is congruent.

(1) BAC could be 40 or (180-40)/2 = 70. NOT sufficient.

Strike A/D.

(2) BAC cannot be 100, because the third angle would have to be negative. There is an implicit constraint that each angle is non-negative. BAC must therefore be (180-100)/2 = 40. Sufficient.

The answer is B.
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Re: Triangle ABC is isosceles. What is the measure of angle BAC? [#permalink]

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Re: Triangle ABC is isosceles. What is the measure of angle BAC?   [#permalink] 16 Feb 2017, 06:13
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