SOLU lets first find out when they both will meet
as we all know both cyclist are coming towards each other they will meet soon so total distance must be divided by sum of their speed.
total distance will be 400 meters circumference of circle
so 400/10+5= 400/15
=80/3 in every 80/3 seconds they will meet
so in 40 min they will meet
40*60(convert in seconds)
we will divide total time with they took time to meet once so to identify how many times they met.
40*60*3/80
=90
so OA IS D

Find combined rate per minute. (R + R). Find time required to cross paths one time (D/R).
Finally, divide total time by time per crossing. Answer equals the # of times they meet.

Convert seconds to minutes

If time units are different, you can convert X seconds to one minute. Multiply the rate's number of seconds by N to get to 60 seconds. Multiply the numerator by N, too.

Rate of Boy 1:
\((\frac{10m}{1sec}*\frac{60}{60})=(\frac{600m}{60secs})=\frac{600m}{1min}\)

Rate of Boy 2:
\((
\frac{5m}{1sec})=(\frac{300m}{60secs})=\frac{300m}{1min}\)

Add rates

When travelers move in opposite directions, whether towards or away from one another, add rates (speeds). Combined rate:

\(\frac{600m}{1min} + \frac{300m}{1min}=\frac{900m}{1min}\)

Time it takes for them to cross paths once?

\(R*T = D\), so \(T=\frac{D}{R}\)

\(T=\frac{400m}{900\frac{meters}{minute}}=\frac{400}{900}mins=\frac{4}{9}min\)

for them to meet once

Number of times they cross/meet?

\(\frac{TotalMinutes}{MinutesPerOneMeet}=\) # of times they meet

\(\frac{40}{\frac{4}{9}}=40*\frac{9}{4}=90\) times that they meet

Answer D