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09 Sep 2019, 23:52
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Two cars are traveling on the same road towards each other. If car A is traveling at a speed of 120 Km/h and car B is traveling 15% slower, how much time will it take the cars to meet if the initial distance between the two is 668.4 Km and car A started to drive one hour and a half before car B started?
A. one hours and 30 minutes.
B. two hours.
C. two hours and 12 minutes.
D. three hours and 15 minutes.
E. three hours and 18 minutes.
A. one hours and 30 minutes.
B. two hours.
C. two hours and 12 minutes.
D. three hours and 15 minutes.
E. three hours and 18 minutes.
10 Sep 2019, 02:28
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Bunuel
Two cars are traveling on the same road towards each other. If car A is traveling at a speed of 120 Km/h and car B is traveling 15% slower, how much time will it take the cars to meet if the initial distance between the two is 668.4 Km and car A started to drive one hour and a half before car B started?
A. one hours and 30 minutes.
B. two hours.
C. two hours and 12 minutes.
D. three hours and 15 minutes.
E. three hours and 18 minutes.
A. one hours and 30 minutes.
B. two hours.
C. two hours and 12 minutes.
D. three hours and 15 minutes.
E. three hours and 18 minutes.
net relative speed of A&B ; 120+120*.85 ; 222 kmph
and distance covered by A in 3/2 hrs ; 3/2*120 ' 180 kms
so net distance left ; 668.4-180 ; 488.4 km
time taken would be 488.4/222 ; 2 hrs 12 mins
IMO C
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28 Oct 2019, 01:44
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First determine the rates.
85/100 * 120 = 102km
The distance at which the two objects meet is equal to the sum of each individual objects distance travelled.
RateA*Time Travelled A + Rate B* Time Travelled(B) = Distance that separated the two items
Rate | Time Travelled| Distance
120km/hr | 1.5 + T | 180 +120T
102km/hr | T (T=time)| 102T
120T + 1.5*120 + 102T = 688.4
222T = 668.4-180
222T = 488.4 (I converted to a fraction to make it easier)
222T = 4884/10
2220T =4884
1110T = 2442
T = 2442/ 1110 = 2.2
without doing any further calculations we can see that we have 2 hours + some change, so the only answer that gets this is C
85/100 * 120 = 102km
The distance at which the two objects meet is equal to the sum of each individual objects distance travelled.
RateA*Time Travelled A + Rate B* Time Travelled(B) = Distance that separated the two items
Rate | Time Travelled| Distance
120km/hr | 1.5 + T | 180 +120T
102km/hr | T (T=time)| 102T
120T + 1.5*120 + 102T = 688.4
222T = 668.4-180
222T = 488.4 (I converted to a fraction to make it easier)
222T = 4884/10
2220T =4884
1110T = 2442
T = 2442/ 1110 = 2.2
without doing any further calculations we can see that we have 2 hours + some change, so the only answer that gets this is C
