DisciplinedPrep
Two cars, which are x miles apart, take
u minutes to pass each other when they are moving towards each other, and
v minutes to meet each other when they are moving in the same direction. Find the ratio of the rate of the slower car to that of the faster car.
A. \(\frac{u}{v}\)
B. \(\frac{u}{v-u}\)
C. \(\frac{v−u}{v+u}\)
D. \(\frac{u}{v+u}\)
E. \(\frac{v}{v+u}\)
Let the speed of car be a and b.
Two cases are given
1)
Cars moving towards each other: Distance traveled = d, and speed will be the combined speed of the two cars = a+b
So, \(\frac{d}{a+b}=u......d=u(a+b)\)
2)
Cars moving in same direction: The faster car has to cover the distance between them to catch up with the slower car.
Distance traveled = d, and relative speed = a-b
So, \(\frac{d}{a-b}=v.....d=v(a-b)\)
Equating the values of d
\(u(a+b)=v(a-b)..........ua+ub=va-vb........va-ua=vb+ub\)
\(a(v-u)=b(v+u)............\frac{a}{b}=\frac{v+u}{v-u}...\ \ or \ \....\frac{b}{a}=\frac{v-u}{v+u}\)
C