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21 Nov 2023, 10:44
Kudos
Bookmarks
Jack's: 125
Sam's: 125
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
40% (03:46) correct
60%
(03:51)
wrong
based on 166
sessions
History
Date
Time
Result
Not Attempted Yet
Two companies are competing against one another for a contract to provide basic vehicle maintenance for another company that maintains a fleet of 300 cars for its sales agents. Jack's Tire and Lube offers on-site maintenance for $42.00 per car.
Care includes basic oil-change services, changing wiper blades and filters as needed, and checking and filling all the car's fluids and tires every 3,000 miles. Major repairs are then referred to a partner company that offers a 20% discount to Jack's clients.
Sam's Service Express offers off-site maintenance for $38.00 per car. Care includes basic oil-changing services, changing wiper blades and filters as needed, and checking and filling all the car's fluids and tires every 3,000 miles. Major repairs are completed by Sam's company at the site where basic maintenance is performed. Sam's offers a 10% discount to contract clients.
Each company requires that a minimum of 100 cars be put on their service. The CEO who must arrange the contracts can see benefits in both service agreements. He has exactly $10,000 to spend on car service contracting. He wants to ensure that the older cars in the fleet are on Jack's service plan. Roughly one-third of the cars in the fleet are more than 2 years old and have high mileage.
How many cars in his fleet should be put on each plan to spend the $10,000 budget exactly? Make only one selection in each column.
Care includes basic oil-change services, changing wiper blades and filters as needed, and checking and filling all the car's fluids and tires every 3,000 miles. Major repairs are then referred to a partner company that offers a 20% discount to Jack's clients.
Sam's Service Express offers off-site maintenance for $38.00 per car. Care includes basic oil-changing services, changing wiper blades and filters as needed, and checking and filling all the car's fluids and tires every 3,000 miles. Major repairs are completed by Sam's company at the site where basic maintenance is performed. Sam's offers a 10% discount to contract clients.
Each company requires that a minimum of 100 cars be put on their service. The CEO who must arrange the contracts can see benefits in both service agreements. He has exactly $10,000 to spend on car service contracting. He wants to ensure that the older cars in the fleet are on Jack's service plan. Roughly one-third of the cars in the fleet are more than 2 years old and have high mileage.
How many cars in his fleet should be put on each plan to spend the $10,000 budget exactly? Make only one selection in each column.
| Jack's | Sam's | Contracted cars |
| 100 | ||
| 125 | ||
| 130 | ||
| 155 | ||
| 180 | ||
| 237 |
ShowHide Answer
Official Answer
Jack's: 125
Sam's: 125
27 Nov 2023, 12:35
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Official Explanation
The correct answer is 125 cars for each company.
More than one-third of the cars in the fleet must be covered by Jack's service plan. This is the only qualifier for how many cars should be on each plan. So at least 100 cars should be on Jack's plan.
Set up an equation for the total cost of the cars on each service plan, which must equal exactly $10,000 : 38$ + 42J = 10,000. Start with the lowest number, and plug in 100 for S. This equals 38(100) + 42J = 10,000. In this case, J would equal a decimal number, 147.62.
Plug in the next highest number, 125, for $ : 38(125) + 427 = 10,000. in this case, J would also equal 125. Both companies would service the same number of cars.
The correct answer is 125 cars for each company.
More than one-third of the cars in the fleet must be covered by Jack's service plan. This is the only qualifier for how many cars should be on each plan. So at least 100 cars should be on Jack's plan.
Set up an equation for the total cost of the cars on each service plan, which must equal exactly $10,000 : 38$ + 42J = 10,000. Start with the lowest number, and plug in 100 for S. This equals 38(100) + 42J = 10,000. In this case, J would equal a decimal number, 147.62.
Plug in the next highest number, 125, for $ : 38(125) + 427 = 10,000. in this case, J would also equal 125. Both companies would service the same number of cars.
30 Jun 2024, 12:37
Kudos
Bookmarks
42x + 38y = 10000
Plug values
x= 125 and y=125 will satisfy.
Plug values
x= 125 and y=125 will satisfy.
