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Two congruent triangles were combined in three different ways, as show [#permalink]
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Using the rectangle we can see that we have 3 different sides making up the triangle. Let the breadth be x, length be y and the diagonal be z.

All 3 of the shapes' perimeters are comprised of 2 sets of 2 of these (each shape having 4 sides in total).

Rectangle: 2(x+y) = 12
x+y = 6

Diamond shape under the rectangle: 2(z+y) = 14
z+y = 7


Mirrored triangles to the right of the rectangle: 2(z+x) =16
z+x = 8


Summing these together we get: x+y+z+y+z+x = 6+7+8
2x + 2y + 2z = 21
Now we know that a single triangle's perimeter comprises of x+y+z so we divide through by 2 to get:
x+y+z = 21/2

Answer C
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Re: Two congruent triangles were combined in three different ways, as show [#permalink]
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Re: Two congruent triangles were combined in three different ways, as show [#permalink]
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