Method 1: Logic
Two fair six-sided dice, each numbered 1 to 6, are rolled once. What is the probability of getting exactly one even numbers ? As we are rolling two fair dice so there is equal probability of getting any of the following cases
(E,E), (E,O), (O,E), (O,O) where O is Odd and E is Even
P(Getting exactly one even number) = Probability of getting (E,O), (O,E) = \(\frac{2}{4}\) = \(\frac{1}{2}\)
Method 2: AlgebraTwo fair six-sided dice, each numbered 1 to 6, are rolled once. As we are rolling 2 dice => Number of cases = \(6^2\) = 36
What is the probability of getting exactly one even numbers ? P(exactly one even number) = P(Even in 1st and Odd in 2nd) + P(Odd in 1st and Even in 2nd) = \(\frac{1}{2}\) * \(\frac{1}{2}\) + \(\frac{1}{2}\) * \(\frac{1}{2}\) = \(\frac{1}{4}\) + \(\frac{1}{4}\) = \(\frac{1}{2}\)
So,
Answer will be BHope it helps!
Playlist on Solved Problems on Probability hereWatch the following video to MASTER Dice Rolling Probability Problems