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Two number cubes with six faces numbered with the integers from 1 thro

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Two number cubes with six faces numbered with the integers from 1 thro  [#permalink]

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New post 17 Dec 2018, 02:39
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

79% (02:04) correct 21% (02:38) wrong based on 41 sessions

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Joined: 18 Aug 2017
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Concentration: Sustainability, Marketing
GPA: 4
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Two number cubes with six faces numbered with the integers from 1 thro  [#permalink]

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New post Updated on: 17 Dec 2018, 04:45
1
Bunuel wrote:
Two number cubes with six faces numbered with the integers from 1 through 6 are tossed. What is the probability that the sum of the exposed faces on the cubes is a prime number?

A. 1/36
B. 1/8
C. 1/12
D. 5/12
E. 7/12



Favourable events - (1,1), (1,2), (1,4), (2,3), (2,5), (5,6), (3,4), (1,6). Except the event (1,1) every other event must be counted twice due to the fact that the number might appear on either of the dice, so total number of favourable events is 15.

Total events = 6^2 = 36

Probability = 15/36 = 5/12.'
IMO D

Originally posted by Archit3110 on 17 Dec 2018, 04:19.
Last edited by Archit3110 on 17 Dec 2018, 04:45, edited 1 time in total.
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Re: Two number cubes with six faces numbered with the integers from 1 thro  [#permalink]

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New post 17 Dec 2018, 04:40
Isn’t this wrong? Sets should be;
1,1
1,2
1,4
1,6
2,3
2,5
3,4
5,6

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Re: Two number cubes with six faces numbered with the integers from 1 thro  [#permalink]

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New post 17 Dec 2018, 09:49
Bunuel wrote:
Two number cubes with six faces numbered with the integers from 1 through 6 are tossed. What is the probability that the sum of the exposed faces on the cubes is a prime number?

A. 1/36
B. 1/8
C. 1/12
D. 5/12
E. 7/12



Prime numbers between 2 and 12 and the number of ways they can be rolled:
2 (1)
3 (2)
5 (4)
7 (6)
11 (2)

So, 15 total ways to roll a prime. 15/36 = 5/12

ANSWER D
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Re: Two number cubes with six faces numbered with the integers from 1 thro   [#permalink] 17 Dec 2018, 09:49
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