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02 Mar 2026, 14:11
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
75% (03:03) correct
25%
(03:22)
wrong
based on 20
sessions
History
Date
Time
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Not Attempted Yet
Two square rooms have sides of length x feet and y feet, respectively. The length of each side of the larger room is 800% greater than the length of each side of the smaller room. The area of the larger room exceeds the area of the smaller room by 2000 square feet. If the rent for each room is $2.50 per square foot per month, what is the total monthly rent for the two rooms combined?
A. $4,100
B. $4,500
C. $5,000
D. $5,125
E. $5,250
A. $4,100
B. $4,500
C. $5,000
D. $5,125
E. $5,250
02 Mar 2026, 22:07
Kudos
Bookmarks
kevincan
Two square rooms of length x and y feet respectively.
Length of the larger room = x , and the Length of the smaller room = y.
Given that x = 1+(800/100) y
x = 9y
Area of the squares = 81y^2 and y^2
Difference = 81y^2 - y^2 = 80y^2
80y^2 = 2000
y^2 = 25
y=5
sides of square are 45 and 5.
Area = 45^2 and 5^2
Total Area = 2025 + 25 = 2050 square foot.
Rent per square foot = $2.50
Total monthly rent = 2050 * $2.50 = $5,125
Option D
