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26 Mar 2026, 22:52
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
58% (03:01) correct
42%
(02:24)
wrong
based on 45
sessions
History
Date
Time
Result
Not Attempted Yet
Two trains depart at the same time from Dunhill and Stanton and travel toward each other along the same track at constant speeds. They pass each other at 11:55 AM at a point that is one-fourth of the total distance from Dunhill. If the train from Stanton arrives at Dunhill at 12:20 PM, at what time does the train from Dunhill arrive at Stanton?
A. 1:10 PM
B. 1:35 PM
C. 2:00 PM
D. 3:00 PM
E. 3:40 PM
A. 1:10 PM
B. 1:35 PM
C. 2:00 PM
D. 3:00 PM
E. 3:40 PM
27 Mar 2026, 05:11
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Let's start with distance covered by the train from Stanton to Dunhill. It covered 3/4th of the total distance from Stanton (i.e. 1/4th from Dunhill) by 11:55 AM, and reached Dunhill by 12:20 PM, i.e. in 25 minutes.
Since the train from Stanton took 25 minutes to cover 1/4th of the distance, at constant speed, it must've taken 25 x 3 = 75 minutes to cover 3/4th of the distance from the starting point in Stanton, i.e the train had begun it's journey by 10:40 AM.
We can also infer, that the train from Dunhill running towards Stanton had begun it's journey at 10:40 AM and took 75 minutes to cover 1/4th of the total distance by 11:55 AM.
At constant speed, the train from Dunhill will take another 75 x 3 = 225 minutes from 11:55 AM to cover 3/4th of the distance to reach Stanton, i.e. the train will reach Stanton by 3:40 PM.
Correct answer is E.
Since the train from Stanton took 25 minutes to cover 1/4th of the distance, at constant speed, it must've taken 25 x 3 = 75 minutes to cover 3/4th of the distance from the starting point in Stanton, i.e the train had begun it's journey by 10:40 AM.
We can also infer, that the train from Dunhill running towards Stanton had begun it's journey at 10:40 AM and took 75 minutes to cover 1/4th of the total distance by 11:55 AM.
At constant speed, the train from Dunhill will take another 75 x 3 = 225 minutes from 11:55 AM to cover 3/4th of the distance to reach Stanton, i.e. the train will reach Stanton by 3:40 PM.
Correct answer is E.
