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Two worker use 5 days to paint 1 house

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Manager
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Two worker use 5 days to paint 1 house [#permalink]

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New post 10 Nov 2008, 05:43
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Could anyone help me deal with this kind of question esp, when have 3 variables. Thank you very much.

Two worker use 5 days to paint 1 house, if owner requires 6 painted-houses to be finished in 1 day. How many worker owner has to hire?

A. 20
B. 30
C. 40
D. 50
E. 60

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Re: work problem [#permalink]

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New post 10 Nov 2008, 05:52
x = 1 worker/day
H = house painted
m = number of houses
n = number of workers

Formula => mH = nxd

Two worker use 5 days to paint 1 house => mH = H = xnd = 5*2x = 10x

Number of worked required = n = mH/d = 6H/(xd) = 6*10x /x = 60

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Re: work problem [#permalink]

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New post 10 Nov 2008, 05:55
Is the QA E ?

I myself get confused with these kind of qs. I don't know if there's any specific formula , but here's how i would have done it.
2 workers - 5 days - 1 house.
2 workers - 30 days - 6 houses.
1 worker - 60 days - 6 houses.
60 workers - 1 day - 6 houses.

So if we have to do 60 days of job in 1 day, we will need 60 workers.

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New post 10 Nov 2008, 05:59
lylya4 wrote:
x = 1 worker/day
H = house painted
m = number of houses
n = number of workers

Formula => mH = nxd

Two worker use 5 days to paint 1 house => mH = H = xnd = 5*2x = 10x

Number of worked required = n = mH/d = 6H/(xd) = 6*10x /x = 60


What's d stand for?

OA is E, thank you.

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Re: work problem [#permalink]

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New post 10 Nov 2008, 15:48
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Two workers use 5 days to paint 1 house, if owner requires 6 painted-houses to be finished in 1 day. How many worker owner has to hire?

You know that 2 workers = 5days of work so 1 worker = 10 days of work for 1 house if 6 houses are needed, times by 6 = 60 . No need to come up with a formula not enough time. Practice doing this in your head( breaking down the questions).

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Re: work problem [#permalink]

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New post 10 Nov 2008, 16:25
Two worker use 5 days to paint 1 house, if owner requires 6 painted-houses to be finished in 1 day. How many worker owner has to hire?


2 workers paints 1/5 house /day thus 10 workers are needed for 1 house per day thus 60 is the answer
E

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Re: work problem [#permalink]

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New post 10 Nov 2008, 17:54
When you have three variables make one variable constant and move from there.
2 W - 5 days - 1 house

1 W - 10 days - 1 house

1 W - 60 days - 6 houses

? W - 1 day - 6 houses

will need more workers. So its 60/1 X 1 = 60

E

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Re: work problem   [#permalink] 10 Nov 2008, 17:54
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Two worker use 5 days to paint 1 house

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