GMAT Club Official Solution:Two workers, Ava and Ben, are hired to mow a field at a community park. If Ava and Ben work at their respective constant rates, by what percent is the time Ben would take to mow the field alone less than the time Ava would take to mow the field alone?Let A be Ava’s rate and B be Ben’s rate, measured in fields per hour.
Ava’s time to mow the field alone is 1/A.
Ben’s time to mow the field alone is 1/B.
The question asks by what percent 1/B is less than 1/A.
(1) Ben, working alone at his constant rate, would take 2 hours less to mow the field than Ava, working alone at her constant rate, would take.
This gives only the difference between their times, not the percent difference.
For example, if Ava takes 6 hours and Ben takes 4 hours, then Ben’s time is 2 hours less, and the percent decrease is:
2/6 * 100 = 33 1/3%
But if Ava takes 10 hours and Ben takes 8 hours, then Ben’s time is also 2 hours less, and the percent decrease is:
2/10 * 100 = 20%
So the percent can be different.
Not sufficient.
(2) Ava and Ben, working simultaneously and independently at their respective constant rates, can mow the field in 3/5 of the time that Ben, working alone at his constant rate, would take to mow the field.
Since Ava’s rate is A and Ben’s rate is B, their combined rate is A + B fields per hour. Since time = work/rate, the time they take together to mow 1 field is:
1/(A + B)
Ben’s time to mow the field alone is:
1/B
So statement (2) gives:
1/(A + B) = 3/5 * 1/B
5B = 3A + 3B
2B = 3A
B/A = 3/2
This gives the ratio of Ben’s rate to Ava’s rate. Since time is the reciprocal of rate, it also gives the ratio of Ben’s time to Ava’s time. Therefore, we can answer the question.
For reference:
Ben’s rate : Ava’s rate = 3 : 2
So Ben’s time : Ava’s time = 2 : 3
Thus, Ben’s time is 1/3 less than Ava’s time, or 33 1/3% less.
Sufficient.
Answer: B.