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Mo2men
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If they're talking about divisors of the denominator, then the question must be talking about when in the decimal expansion the entire repeating set of digits appears for the second time, and not about when any individual digit repeats. It's definitely not a GMAT question, and there isn't any reason to look at it, but under that interpretation, the right answer will be 53/280. I don't know how anyone could answer this quickly without knowing that in the decimal expansions of both 1/7 and 1/13, you will find a repeating pattern that is 6 digits long -- and you certainly do not need to know that for the GMAT. You'll find a repeating pattern of six digits (eventually) in the decimal equivalent of fraction in the list besides 3/50, since each has a denominator you can obtain from 7 or 13 by dividing by 2s and 5s. If you know that the repeating pattern is six digits long, then it's just a matter of working out how many of the early digits in the decimal expansions of each fraction will not belong to that repeating pattern. You can do that in a few ways - it's possible long division is fastest if you know when you want to stop doing it for each decimal, but I did things like this for each fraction:

53/280 = 28/280 + 21/280 + 4/280 = 1/10 + 3/40 + 1/70 = 0.1 + 0.075 + (0.1)(1/7)

from which you can see that the first three digits of the decimal won't be part of the repeating pattern (because we're modifying them by adding 0.175) but then the repeating pattern will begin in a cycle of six digits, because that's the length of the repeating pattern in the decimal expansion of 1/7.

But it's honestly a completely pointless question to study if you're practicing for the GMAT, which is why I'm only glossing over a solution above.

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