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14 Jun 2021, 06:15
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
60% (01:58) correct
40%
(02:08)
wrong
based on 264
sessions
History
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Not Attempted Yet
Using the digits 1, 2, 3 and 4, some two digit numbers can be formed (repetition allowed). The sum of these numbers is AA0. AA is:
(A) 11
(B) 22
(C) 33
(D) 44
(E) 55
(A) 11
(B) 22
(C) 33
(D) 44
(E) 55
14 Jun 2021, 07:54
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Bunuel
If digits can be repeated, we have four choices for each digit, so we can make 4*4 = 16 different numbers. If we look only at the tens digits of these numbers, in four of them the tens digit will be 1, in four of them it will be 2, and so on. So adding only the tens digits first, they will sum to 4(10 + 20 + 30 + 40) = 4*100 = 400. But the same happens with the units digits; they sum to 4(1 + 2 + 3 + 4) = 40. So all of the numbers sum to 400 + 40 = 440, and D is the answer.
I don't recognize the source in the tag -- where is the question from? The wording of this question is not good. When it says "two digit numbers can be formed (repetition allowed)", it sounds like we are 'allowed' to repeat the two-digit numbers here (e.g. it sounds like we maybe should count "43" multiple times, for some reason). It means to say the digits themselves can be repeated, not that the two-digit numbers can be.
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General Discussion
14 Jun 2021, 07:38
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Total possible two digit numbers: 4*4 = 16
Smallest two digit number possible: 11
Largest two digit number possible: 44
16/2(11+44)
= 8(55)
= 440
Answer D
Smallest two digit number possible: 11
Largest two digit number possible: 44
16/2(11+44)
= 8(55)
= 440
Answer D
