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Vertices of a triangle have coordinates (-2, 2) (3, 2) (x,

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Vertices of a triangle have coordinates (-2, 2) (3, 2) (x, [#permalink]

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New post 06 Nov 2008, 10:23
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Vertices of a triangle have coordinates
(-2, 2)
(3, 2)
(x, y)

What is the area of a triangle?

1. |y - 2| = 1
2. angle at the vertex \((x, y)\) equals 90 degrees

I get base = 5.
Y is either 3 or 1.
how do we find the height as x could be any value?

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Re: Geometry [#permalink]

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New post 06 Nov 2008, 10:28
[ think its C..

cause if y=+-3 then the base is 5..and hight is 5..



quote="study"]Vertices of a triangle have coordinates
(-2, 2)
(3, 2)
(x, y)

What is the area of a triangle?

1. |y - 2| = 1
2. angle at the vertex \((x, y)\) equals 90 degrees

I get base = 5.
Y is either 3 or 1.
how do we find the height as x could be any value?[/quote]

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Re: Geometry [#permalink]

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New post 06 Nov 2008, 12:54
shud be A

you know the base is 5

now with 1 you know that the height is 1 , COZ y=3,1

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Re: Geometry [#permalink]

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New post 07 Nov 2008, 05:15
Agree with A.

Stmt1 gives the y co-ordinates and hence the height of the triangle (as the base is parallel to X-axis).

Stmt2 on its own does not give any information.

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Re: Geometry [#permalink]

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New post 07 Nov 2008, 09:26
scthakur wrote:
Agree with A.

Stmt1 gives the y co-ordinates and hence the height of the triangle (as the base is parallel to X-axis).

Stmt2 on its own does not give any information.


If y can be 3 or 1 how can we deduce the height? Am I missing some thing obvious here?

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Re: Geometry [#permalink]

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New post 07 Nov 2008, 09:52
if y can be 1 or 3, how is this sufficient???

can you please post the OE?

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Re: Geometry [#permalink]

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New post 07 Nov 2008, 11:45
icandy wrote:
scthakur wrote:
Agree with A.

Stmt1 gives the y co-ordinates and hence the height of the triangle (as the base is parallel to X-axis).

Stmt2 on its own does not give any information.


If y can be 3 or 1 how can we deduce the height? Am I missing some thing obvious here?


The base of the triangle (with two known vertices) are at a height of 2 from the origin. The third vertex being either at 3 or at 1 will give the same height (3-2) or (2-1). Hence, A is sufficient.

It will be better to draw the triangle and visualize. That will make it more clear.

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Re: Geometry [#permalink]

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New post 07 Nov 2008, 12:11
i did and its not very clear to me..

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Re: Geometry [#permalink]

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New post 07 Nov 2008, 12:20
scthakur wrote:
icandy wrote:
scthakur wrote:
Agree with A.

Stmt1 gives the y co-ordinates and hence the height of the triangle (as the base is parallel to X-axis).

Stmt2 on its own does not give any information.


If y can be 3 or 1 how can we deduce the height? Am I missing some thing obvious here?


The base of the triangle (with two known vertices) are at a height of 2 from the origin. The third vertex being either at 3 or at 1 will give the same height (3-2) or (2-1). Hence, A is sufficient.

It will be better to draw the triangle and visualize. That will make it more clear.


Agree. It does not matter if y=3 or y=1, the height of the triangle with the base of 5 is always equal to 1. It also means that it does not matter what the value of x is.
So i agree with A.

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Re: Geometry [#permalink]

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New post 07 Nov 2008, 12:49
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fresinha12 wrote:
i did and its not very clear to me..


I have tried one diagram (not a good one). The base is AB and height is 1 (of triangle ABC).
Attachments

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untitled.JPG [ 6.92 KiB | Viewed 663 times ]

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Re: Geometry [#permalink]

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New post 07 Nov 2008, 18:07
Thanks for the picture and I understood it now. The height of the triangle drawn from the vertex to the base is a line parallel to the y axis. X does not matter and 3-2 is 1 and 2-1 is 1. hence height is 1

+1 scthakur

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Re: Geometry   [#permalink] 07 Nov 2008, 18:07
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