It is currently 22 Mar 2018, 20:29

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Vertices of a triangle have coordinates (-2, 2) (3, 2) (x,

Author Message
Senior Manager
Joined: 05 Oct 2008
Posts: 263
Vertices of a triangle have coordinates (-2, 2) (3, 2) (x, [#permalink]

### Show Tags

06 Nov 2008, 10:23
Vertices of a triangle have coordinates
(-2, 2)
(3, 2)
(x, y)

What is the area of a triangle?

1. |y - 2| = 1
2. angle at the vertex $$(x, y)$$ equals 90 degrees

I get base = 5.
Y is either 3 or 1.
how do we find the height as x could be any value?

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Current Student
Joined: 28 Dec 2004
Posts: 3311
Location: New York City
Schools: Wharton'11 HBS'12

### Show Tags

06 Nov 2008, 10:28
[ think its C..

cause if y=+-3 then the base is 5..and hight is 5..

quote="study"]Vertices of a triangle have coordinates
(-2, 2)
(3, 2)
(x, y)

What is the area of a triangle?

1. |y - 2| = 1
2. angle at the vertex $$(x, y)$$ equals 90 degrees

I get base = 5.
Y is either 3 or 1.
how do we find the height as x could be any value?[/quote]
Senior Manager
Joined: 31 Jul 2008
Posts: 280

### Show Tags

06 Nov 2008, 12:54
shud be A

you know the base is 5

now with 1 you know that the height is 1 , COZ y=3,1
SVP
Joined: 17 Jun 2008
Posts: 1503

### Show Tags

07 Nov 2008, 05:15
Agree with A.

Stmt1 gives the y co-ordinates and hence the height of the triangle (as the base is parallel to X-axis).

Stmt2 on its own does not give any information.
VP
Joined: 05 Jul 2008
Posts: 1369

### Show Tags

07 Nov 2008, 09:26
scthakur wrote:
Agree with A.

Stmt1 gives the y co-ordinates and hence the height of the triangle (as the base is parallel to X-axis).

Stmt2 on its own does not give any information.

If y can be 3 or 1 how can we deduce the height? Am I missing some thing obvious here?
Current Student
Joined: 28 Dec 2004
Posts: 3311
Location: New York City
Schools: Wharton'11 HBS'12

### Show Tags

07 Nov 2008, 09:52
if y can be 1 or 3, how is this sufficient???

can you please post the OE?
SVP
Joined: 17 Jun 2008
Posts: 1503

### Show Tags

07 Nov 2008, 11:45
icandy wrote:
scthakur wrote:
Agree with A.

Stmt1 gives the y co-ordinates and hence the height of the triangle (as the base is parallel to X-axis).

Stmt2 on its own does not give any information.

If y can be 3 or 1 how can we deduce the height? Am I missing some thing obvious here?

The base of the triangle (with two known vertices) are at a height of 2 from the origin. The third vertex being either at 3 or at 1 will give the same height (3-2) or (2-1). Hence, A is sufficient.

It will be better to draw the triangle and visualize. That will make it more clear.
Current Student
Joined: 28 Dec 2004
Posts: 3311
Location: New York City
Schools: Wharton'11 HBS'12

### Show Tags

07 Nov 2008, 12:11
i did and its not very clear to me..
Manager
Joined: 15 Oct 2008
Posts: 103

### Show Tags

07 Nov 2008, 12:20
scthakur wrote:
icandy wrote:
scthakur wrote:
Agree with A.

Stmt1 gives the y co-ordinates and hence the height of the triangle (as the base is parallel to X-axis).

Stmt2 on its own does not give any information.

If y can be 3 or 1 how can we deduce the height? Am I missing some thing obvious here?

The base of the triangle (with two known vertices) are at a height of 2 from the origin. The third vertex being either at 3 or at 1 will give the same height (3-2) or (2-1). Hence, A is sufficient.

It will be better to draw the triangle and visualize. That will make it more clear.

Agree. It does not matter if y=3 or y=1, the height of the triangle with the base of 5 is always equal to 1. It also means that it does not matter what the value of x is.
So i agree with A.
SVP
Joined: 17 Jun 2008
Posts: 1503

### Show Tags

07 Nov 2008, 12:49
1
KUDOS
fresinha12 wrote:
i did and its not very clear to me..

I have tried one diagram (not a good one). The base is AB and height is 1 (of triangle ABC).
Attachments

untitled.JPG [ 6.92 KiB | Viewed 715 times ]

VP
Joined: 05 Jul 2008
Posts: 1369

### Show Tags

07 Nov 2008, 18:07
Thanks for the picture and I understood it now. The height of the triangle drawn from the vertex to the base is a line parallel to the y axis. X does not matter and 3-2 is 1 and 2-1 is 1. hence height is 1

+1 scthakur

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: Geometry   [#permalink] 07 Nov 2008, 18:07
Display posts from previous: Sort by

# Vertices of a triangle have coordinates (-2, 2) (3, 2) (x,

Moderator: chetan2u

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.