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Stmt1 gives the y co-ordinates and hence the height of the triangle (as the base is parallel to X-axis).

Stmt2 on its own does not give any information.

If y can be 3 or 1 how can we deduce the height? Am I missing some thing obvious here?

The base of the triangle (with two known vertices) are at a height of 2 from the origin. The third vertex being either at 3 or at 1 will give the same height (3-2) or (2-1). Hence, A is sufficient.

It will be better to draw the triangle and visualize. That will make it more clear.

Stmt1 gives the y co-ordinates and hence the height of the triangle (as the base is parallel to X-axis).

Stmt2 on its own does not give any information.

If y can be 3 or 1 how can we deduce the height? Am I missing some thing obvious here?

The base of the triangle (with two known vertices) are at a height of 2 from the origin. The third vertex being either at 3 or at 1 will give the same height (3-2) or (2-1). Hence, A is sufficient.

It will be better to draw the triangle and visualize. That will make it more clear.

Agree. It does not matter if y=3 or y=1, the height of the triangle with the base of 5 is always equal to 1. It also means that it does not matter what the value of x is. So i agree with A.

Thanks for the picture and I understood it now. The height of the triangle drawn from the vertex to the base is a line parallel to the y axis. X does not matter and 3-2 is 1 and 2-1 is 1. hence height is 1