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Strategy: Using a relative number line + treat like a data sufficiency question.

Let's try to draw out our skeleton number line using the question.
1) X melts at a higher temperature than P melts. => X will be to the right of P in the number line.

2) Y melts at a lower temperature than P melts, but at a higher temperature than Q melts. => Y will be to the left of P. Q will be to the left of Y.

--Q--Y---P---X--

Quote:
If the statements above are true, it can be concluded with certainty that S melts at a higher temperature than Y melts if one knows in addition that
=> This would mean S would be to the right of Y. But we don't know S's location with respect to P and X.

(A) Q and P melt at a higher temperature than S melts => --S--Q--Y---P---X-- => Is S to the right of Y? No. Incorrect.

(B) X melts at a higher temperature than S melts => --(S)--Q--Y--(S)-P---X => Treat this like a data sufficiency question. S will be to the left of X. But we don't know the relative position of S wrt to Y. S could be at the extreme left of the line, which would make our question stem untrue OR S could be between Y and X, which would make the question stem correct. Since we don't have a definite Yes/No, this option is incorrect.

(C) P melts at a lower temperature than S melts. --Q--Y--P-(S)--X-- => S will be to the right of P, hence S will always be to the right of Y. Correct: S will burn at a higher temperature than Y.

(D) Q melts at the same temperature that S melts. --(S)Q--Y--P---X-- => Since Q is burning at a lower temp than Y, S will also be burning at a lower temp than Y. Makes our question stem false. Incorrect.

(E) S melts at a higher temperature than Q melts. --Q--(S)--Y--P---X--(S) => As with Option B, there are two positions of S relative to Y, which doesn't give us a definite Yes/No. Incorrect.
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X melts at a higher temperature than P melts. Y melts at a lower temperature than P melts, but at a higher temperature than Q melts.

If the statements above are true, it can be concluded with certainty that S melts at a higher temperature than Y melts if one knows in addition that

(A) Q and P melt at a higher temperature than Smelts
(B) X melts at a higher temperature than Smelts
(C) P melts at a lower temperature than Smelts
(D) Q melts at the same temperature that Smelts
(E) S melts at a higher temperature than Q melts


Kudos for the right answer and explanation

The correct answer is (C). Took me a min and 30 seconds .

It can be easily solved if you have this diagram in mind : In the decreasing order of temp melting it is:
P
Y X somewhat here or lower
Q

So if P melts at lower temp than S , that suffices that S melts at a higher temp than Y.
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