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25 Jun 2025, 00:30
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
52% (02:13) correct
48%
(02:18)
wrong
based on 212
sessions
History
Date
Time
Result
Not Attempted Yet
You have three boxes, each containing two balls, one containing a black pair; one, a white pair; and the third, one white ball and one black ball. On each block are pictures of two balls-either two black ones, two white ones, or one white and one black.
You are told that the markings on the boxes are all wrong. You are asked to ascertain the colors of the balls contained in each box.
Which of the following statements can be inferred from the above?
(A) You can take out one ball from the box marked with two black balls and, without looking at the second ball, know what is box actually contains.
(B) You can take out one ball from the box marked with two white balls and, without looking at the second ball, know what is box actually contains.
(C) You can take out one ball from the box marked with one white ball and one black ball and, without looking at the second ball, know what is box contains.
(D) You cannot know which balls are contained in which box until you take a ball out of more than one box.
(E) You cannot know which boxes contain which color balls until you take a ball out of all three boxes.
You are told that the markings on the boxes are all wrong. You are asked to ascertain the colors of the balls contained in each box.
Which of the following statements can be inferred from the above?
(A) You can take out one ball from the box marked with two black balls and, without looking at the second ball, know what is box actually contains.
(B) You can take out one ball from the box marked with two white balls and, without looking at the second ball, know what is box actually contains.
(C) You can take out one ball from the box marked with one white ball and one black ball and, without looking at the second ball, know what is box contains.
(D) You cannot know which balls are contained in which box until you take a ball out of more than one box.
(E) You cannot know which boxes contain which color balls until you take a ball out of all three boxes.
25 Jun 2025, 01:52
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Consider this
Box 1 contains picture of two black balls
Box 2 contains picture of two white balls
Box 3 contains picture of one white and one black ball
It is also said that the picture lies
(A) You can take out one ball from the box marked with two black balls and, without looking at the second ball, know what is box actually contains.
This means this Box either contain 2 white balls or one white and one black ball
If I take out one black ball then it's certain that it's the box with one white and one black
But if I take out one white ball then we can't say which box it is.
So wrong inference
(B) You can take out one ball from the box marked with two white balls and, without looking at the second ball, know what is box actually contains.
So this box either contain two black balls or one black and one white ball
If I take out white ball then it's certain that it contains one black and one white ball but if I take out black ball then we can't say
So wrong inference
(C) You can take out one ball from the box marked with one white ball and one black ball and, without looking at the second ball, know what is box contains.
We know that this box either contain two white balls or two black balls
So if I take out white ball then it's sure that other ball is white
If I take out black ball then it's sure that other ball is black
So this inference is correct.
(D) You cannot know which balls are contained in which box until you take a ball out of more than one box.
As said in C, if we got to know about the box in C then we can say what that box contain So this option is ruled out
(E) You cannot know which boxes contain which color balls until you take a ball out of all three boxes.
Same as D this is also ruled out.
So option C
Box 1 contains picture of two black balls
Box 2 contains picture of two white balls
Box 3 contains picture of one white and one black ball
It is also said that the picture lies
(A) You can take out one ball from the box marked with two black balls and, without looking at the second ball, know what is box actually contains.
This means this Box either contain 2 white balls or one white and one black ball
If I take out one black ball then it's certain that it's the box with one white and one black
But if I take out one white ball then we can't say which box it is.
So wrong inference
(B) You can take out one ball from the box marked with two white balls and, without looking at the second ball, know what is box actually contains.
So this box either contain two black balls or one black and one white ball
If I take out white ball then it's certain that it contains one black and one white ball but if I take out black ball then we can't say
So wrong inference
(C) You can take out one ball from the box marked with one white ball and one black ball and, without looking at the second ball, know what is box contains.
We know that this box either contain two white balls or two black balls
So if I take out white ball then it's sure that other ball is white
If I take out black ball then it's sure that other ball is black
So this inference is correct.
(D) You cannot know which balls are contained in which box until you take a ball out of more than one box.
As said in C, if we got to know about the box in C then we can say what that box contain So this option is ruled out
(E) You cannot know which boxes contain which color balls until you take a ball out of all three boxes.
Same as D this is also ruled out.
So option C
06 Jul 2025, 17:00
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Bunuel
Official Explanation
(C)
By removing one ball from the box marked with two black balls or removing one ball from the box marked with two white balls, you cannot ascertain the color of the ball left in the box, let alone the color of the balls in the third box. Therefore, answer alternatives (A) and (B) are inappropriate. (D) and (E) are also inappropriate because it is possible by talking out just one ball from the box marked with one white ball and one black ball and ascertain the colors of all the balls contained in each box. The appropriate answer is (C). If you take one ball from the box wrongly marked with one white ball and one black ball, and if the ball is white, it must be one of the white pair. The mixed pair would then have to be in the box marked with two black balls and the remaining box must therefore contain the black pair.
